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newSchoolWorks.com › VoTechWorks › Building & Construction › Electrical › National Electrical Code (NEC) Application for Building & Construction › Lesson 4
BLD-ELEC05-03 · Lesson 4 · 26 clock hours · theory

Article 220 — Load Calculations for Residential Occupancies

Objective. Students will complete a full Article 220 residential load calculation — general lighting, small appliance circuits, laundry, and major appliances — to size a service entrance correctly.

Article 220 — Load Calculations for Residential Occupancies

Why Load Calculations Matter

Before a single wire is pulled in a new home, an electrician must answer one critical question: how large does the service entrance need to be? Size it too small and the service will trip breakers, overheat conductors, and violate the NEC. Size it too large and the homeowner overpays for equipment they do not need. Article 220 of the National Electrical Code (NEC) provides the rules for answering that question correctly and legally.

Every building inspector, utility company, and plan reviewer expects to see a documented load calculation. Learning to do this accurately is a core job skill — and it is tested on both NCCER Level 2 assessments and many state journeyman licensing exams.

Safety Note Before You Start

Load calculation work is design and planning work — you are not yet touching energized equipment. However, the numbers you produce directly affect safety downstream. An undersized service entrance conductor can overheat and start a fire. Always double-check arithmetic, use current code tables, and never guess at demand factors. If you are ever making changes to an existing service, follow lockout/tagout (LOTO) procedures before touching any service equipment, and wear appropriate PPE including safety glasses and insulated gloves rated for the voltage involved.

The Standard Method: Article 220 Parts I–III

The standard (non-optional) calculation method is found in Article 220 Parts I through III. Work through it in this order.

Step 1 — General Lighting and Receptacle Load

For a dwelling unit, the general lighting load is calculated at 3 volt-amperes (VA) per square foot of living area (NEC Table 220.12). Measure the outside dimensions of the structure, excluding open porches, garages, and unfinished spaces not adaptable for future use. Multiply the total square footage by 3 VA/ft².

Step 2 — Small Appliance and Laundry Circuit Loads

The NEC requires a minimum of two 20-ampere small appliance branch circuits for kitchen and dining areas. Each is calculated at 1,500 VA regardless of the actual number of outlets. Add at least one 1,500 VA laundry branch circuit load. These loads are added to the general lighting total before demand factors are applied.

Step 3 — Apply Demand Factors to Lighting and Small Appliance Loads

Table 220.42 allows you to reduce the combined lighting and small appliance load. The first 3,000 VA is taken at 100%. The next portion — from 3,001 VA to 120,000 VA — is taken at 35%. Anything above 120,000 VA returns to 100%. Add the results to get your demand-adjusted lighting load.

Step 4 — Fixed Appliance Loads

List every fixed appliance: dishwasher, garbage disposal, water heater, well pump, and similar loads. Add their nameplate VA (or watts, treated as VA for resistive loads). If there are four or more fixed appliances (not counting ranges, dryers, AC, or heat), you may apply a 75% demand factor to the total.

Step 5 — Dryer Load

Use 5,000 VA or the nameplate rating, whichever is larger, for each electric clothes dryer (NEC 220.54 and Table 220.54). For a single dryer in a dwelling the demand factor is 100%.

Step 6 — Range and Cooking Equipment Load

For household electric ranges rated over 1¾ kW, use NEC Table 220.55. A single range rated up to 12 kW uses a maximum demand of 8,000 VA. Nameplate ratings over 12 kW require adjustments described in the table notes.

Step 7 — Heating or Air Conditioning (Largest Load)

Include only the larger of the heating load or the cooling load — not both — because they do not operate simultaneously. This is the non-coincident load rule.

Step 8 — Total the VA, Convert to Amperes

Add all demand loads together. Divide the total VA by the service voltage to get amperes. For a standard single-phase 120/240 V residential service, divide by 240 V.

> Amperes = Total Demand VA ÷ 240 V

Select the next standard service size at or above the calculated ampere value. Common sizes are 100 A, 150 A, 200 A, and 400 A.

The Optional Method: Article 220 Part IV

Part IV provides a simplified optional calculation. Instead of applying separate demand factors to each load category, it combines all loads and applies a single demand factor from Table 220.84 based on the total connected load and the number of dwelling units. For a single-family dwelling, the optional method often produces a smaller calculated load than the standard method, which can reduce service size and installation cost. However, the optional method is only available when the dwelling has electric heat or air conditioning.

Reading the Tables Accurately

Mistakes in load calculations almost always come from misreading a table. Always confirm you are using the correct table number, reading across the right row, and applying the correct voltage. Carry units (VA, kW, A) through every line of your work so errors are easier to catch.

Connecting to Your Credentials

NCCER Electrical Level 2 includes a full module on load calculations using the same Article 220 framework taught here. State journeyman exams routinely include load calculation problems — some states allow an open-code book, others do not, so know both the method and the table locations. OSHA 10 training reinforces that correctly sized services protect workers and building occupants from electrical fire hazards.

Key terms9

Demand factorA percentage applied to a connected load that accounts for the statistical likelihood that not all loads operate simultaneously at full power, allowing the calculated load to be reduced.
Connected loadThe sum of the nameplate ratings of all electrical equipment installed in a building, before any demand factors are applied.
General lighting loadThe base load assigned to a dwelling calculated at 3 VA per square foot of living area per NEC Table 220.12, covering general lighting and general-use receptacles.
Small appliance branch circuitA 20-ampere circuit required in kitchen and dining areas; each is assigned 1,500 VA for load calculation purposes regardless of actual outlet count.
Non-coincident loadTwo loads that are unlikely to operate at the same time; for residential calculations only the larger of the heating or cooling load is included.
Service entranceThe conductors and equipment that bring electrical power from the utility supply to the building's main distribution panel; sized based on the calculated demand load.
Volt-ampere (VA)The unit used in load calculations representing the product of voltage and current; for resistive loads VA equals watts, but VA is used throughout Article 220 to keep units consistent.
Standard methodThe Article 220 Parts I–III calculation procedure that applies demand factors separately to lighting, small appliance, and individual appliance loads to determine service size.
Optional methodThe simplified single-demand-factor calculation found in Article 220 Part IV, available for dwellings with electric heating or air conditioning, which often yields a lower calculated load.

Worked examples4

1. A single-family dwelling has 1,800 square feet of living area, two small appliance circuits, one laundry circuit, an 8-kW electric range, a 5,500-W electric dryer, a dishwasher (1,200 VA), a garbage disposal (900 VA), and a 3.5-kW central air conditioner. No electric heat. Calculate the standard-method service size.
  1. Step 1 — General lighting: 1,800 ft² × 3 VA/ft² = 5,400 VA
  2. Step 2 — Small appliance circuits: 2 × 1,500 VA = 3,000 VA
  3. Step 3 — Laundry circuit: 1 × 1,500 VA = 1,500 VA
  4. Step 4 — Subtotal before demand factors: 5,400 + 3,000 + 1,500 = 9,900 VA
  5. Step 5 — Apply Table 220.42 demand factors: First 3,000 VA × 100% = 3,000 VA; Remaining 6,900 VA × 35% = 2,415 VA; Demand-adjusted lighting/SA/laundry total = 3,000 + 2,415 = 5,415 VA
  6. Step 6 — Fixed appliances (dishwasher + disposal): 1,200 + 900 = 2,100 VA; only 2 fixed appliances, so no 75% factor applies; fixed appliance demand = 2,100 VA
  7. Step 7 — Dryer: nameplate 5,500 W > 5,000 VA minimum, so use 5,500 VA at 100% = 5,500 VA
  8. Step 8 — Range (8 kW, ≤ 12 kW): per NEC Table 220.55, use 8,000 VA
  9. Step 9 — Air conditioning: 3,500 VA (no heating load to compare, so include AC at 100%): 3,500 VA
  10. Step 10 — Total demand: 5,415 + 2,100 + 5,500 + 8,000 + 3,500 = 24,515 VA
  11. Step 11 — Convert to amperes: 24,515 VA ÷ 240 V = 102.1 A
  12. Step 12 — Select next standard service size at or above 102.1 A = 150 A service
Answer: Required service size: 150 amperes
2. A 1,200 square foot dwelling has two small appliance circuits, one laundry circuit, and no major appliances beyond a 4.5-kW water heater (240 V). What is the demand-adjusted load for just the lighting, small appliance, and laundry portion?
  1. Step 1 — General lighting: 1,200 ft² × 3 VA/ft² = 3,600 VA
  2. Step 2 — Small appliance circuits: 2 × 1,500 VA = 3,000 VA
  3. Step 3 — Laundry circuit: 1 × 1,500 VA = 1,500 VA
  4. Step 4 — Subtotal: 3,600 + 3,000 + 1,500 = 8,100 VA
  5. Step 5 — Apply Table 220.42: First 3,000 VA × 100% = 3,000 VA; Remaining 5,100 VA × 35% = 1,785 VA
  6. Step 6 — Demand-adjusted total: 3,000 + 1,785 = 4,785 VA
Answer: Demand-adjusted lighting/SA/laundry load = 4,785 VA
3. A home has five fixed appliances with a combined nameplate total of 8,000 VA. The dishwasher, disposal, trash compactor, water heater, and well pump each contribute to this total. What is the demand load for these appliances under the standard method?
  1. Step 1 — Count fixed appliances: 5 appliances qualify (ranges, dryers, AC, and heat are excluded from this group)
  2. Step 2 — Because there are four or more fixed appliances, apply the 75% demand factor
  3. Step 3 — Demand load: 8,000 VA × 0.75 = 6,000 VA
Answer: Fixed appliance demand load = 6,000 VA
4. A dwelling has a 10-kW electric furnace and a 4-kW central air conditioner. Which load is included in the service calculation and at what value?
  1. Step 1 — Identify each load: heating = 10,000 VA; cooling = 4,000 VA
  2. Step 2 — Apply the non-coincident load rule: include only the larger load
  3. Step 3 — 10,000 VA (heating) > 4,000 VA (cooling), so use heating load
  4. Step 4 — Include 10,000 VA in the total demand calculation
Answer: Include the heating load at 10,000 VA; the cooling load is omitted.

The math in this lesson2

Learners compute dwelling loads at 3 VA per sq ft, apply demand-factor percentages, and convert VA to service amperes.
7.RP.3N-Q.1
Brush up in the math halls at newSchoolWorks.com:
In class: Step-by-step instructor demonstration: using a provided single-family dwelling floor plan and appliance list, instructor works through the standard (non-optional) calculation method line by line on the whiteboard while students follow along and complete their own copy simultaneously. · Optional method comparison: students repeat the calculation for the same dwelling using the optional method (Article 220 Part IV) and compare the resulting service size with the standard method result, then write a brief paragraph explaining why the results differ. · Group calculation contest: teams receive a new dwelling with different square footage and appliance loads and race to produce the correct service size; teams present results and defend their math to the class.
Materials: NEC Article 220 and associated tables; scientific calculator; load calculation worksheets (instructor-prepared); sample residential floor plans with appliance schedules; NCCER Electrical Level 2 load calculation section
Check: Individual load calculation exam: student completes a full standard-method residential load calculation from a provided dwelling description; must arrive at the correct service size (within one standard service amperage step) and cite the correct table or section for every demand factor applied; 80% of calculation steps correct to pass.

Practice check8

Answer each question, then check it. Nothing is recorded; this is your own practice.

NEC Load Calculations
1. According to NEC Table 220.12, what is the general lighting load assigned to a residential occupancy?
NEC Load Calculations
2. Under the standard method, what demand factor does NEC Table 220.42 assign to the portion of the lighting and small appliance load between 3,001 VA and 120,000 VA?
NEC Branch Circuit Requirements
3. A single-family dwelling requires a minimum of how many 20-ampere small appliance branch circuits for load calculation purposes?
NEC Load Calculations
4. When a dwelling has both a 9-kW electric furnace and a 5-kW central air conditioner, which load is included in the service load calculation under the standard method?
NEC Load Calculations
5. A home has four fixed appliances (dishwasher, disposal, trash compactor, water heater) with a combined nameplate rating of 6,400 VA. What is the demand load used in the calculation?
NEC Appliance Load Calculations
6. For a single household electric clothes dryer with a nameplate rating of 4,800 watts, what load value does Article 220 require you to use in the calculation?
NEC Service Sizing
7. A calculated total demand load for a single-family dwelling equals 26,400 VA on a 120/240 V single-phase service. What is the minimum calculated amperage and which standard service size would be selected?
NEC Load Calculations
8. Which NEC article part contains the optional calculation method for single-family dwellings, and what is typically true about its result compared to the standard method?
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