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BLD-NUCL84-02 · Lesson 3 · 28 clock hours · theory

Fission Chain Reaction and Criticality — The Six-Factor Formula

Objective. Students will define each factor in the six-factor formula (η, ε, p, f, P_TNL, P_FNL), state how each is controlled in a light-water reactor, and calculate the effective multiplication factor k-eff for simplified cases.

⚠ Pending professional review

This lesson, its worked examples and its practice questions has not yet been verified by a licensed professional engineer or master tradesperson or by a certification or approval body. It is a study draft and may contain errors. Do not use it as instructions for work on a job site or on live equipment. Always follow your instructor, your supervising professional, and current official references and regulations.

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What Is a Chain Reaction?

Nuclear fission releases energy when a neutron strikes a fissile nucleus — most commonly uranium-235 in a light-water reactor (LWR) — splitting it and releasing two or three new neutrons. Those neutrons can strike more fissile nuclei, releasing still more neutrons. This self-sustaining sequence is a fission chain reaction. Whether the chain reaction grows, holds steady, or dies out is described by a single number: the effective multiplication factor, k-eff.

Understanding what controls k-eff is foundational to every operator action and safety analysis you will encounter in plant work.

The Six-Factor Formula

For a finite, thermal reactor (like a pressurized-water or boiling-water reactor), k-eff is expressed as the product of six dimensionless factors:

k-eff = η × ε × p × f × P_TNL × P_FNL

Each factor accounts for one physical process that either produces or loses neutrons as they travel from birth to causing the next fission.

η — Reproduction Factor (Eta)

η is the average number of fast neutrons produced per thermal neutron absorbed in fuel. It depends on the fuel isotopic mix (U-235 enrichment) and the fission cross-sections. A typical LWR core has η near 2.0. Control: enrichment level and fuel type are set during fuel fabrication; operators cannot change η during operation.

ε — Fast Fission Factor (Epsilon)

ε accounts for additional fissions caused by fast neutrons before they slow down, primarily in U-238. ε is slightly above 1.0 (roughly 1.02–1.05 in LWRs) and is essentially fixed by fuel geometry. Fast-neutron fissions in U-238 add a small bonus to the neutron population.

p — Resonance Escape Probability

p is the fraction of neutrons that escape capture in U-238 resonance absorption peaks while slowing down from fast to thermal energies. In a well-moderated LWR, p is typically 0.75–0.90. Control: moderator temperature and density affect how quickly neutrons slow down; the more effectively they slow, the higher p. Increasing moderator temperature spreads the neutron energy distribution and can lower p (a safety-relevant effect).

f — Thermal Utilization Factor

f is the fraction of thermal neutrons that are absorbed specifically in fuel, as opposed to in the moderator, structural materials, or neutron poisons. Control: adding soluble boron (boric acid) to the coolant or inserting control rods increases parasitic absorption, lowering f and therefore k-eff. This is the primary mechanism operators use to control reactor power during normal operation.

P_TNL — Thermal Non-Leakage Probability

P_TNL is the probability that a thermal neutron does NOT leak out of the reactor core before it is absorbed. A larger, denser core has a higher P_TNL. Control: core size is fixed by design; however, moderator density (affected by temperature and pressure) influences thermal diffusion length and thus P_TNL.

P_FNL — Fast Non-Leakage Probability

P_FNL is the probability that a fast neutron does NOT leak out before it slows down. Like P_TNL, it is governed primarily by core geometry and reflector design. Surrounding the core with a neutron reflector (water or graphite) increases both non-leakage probabilities.

How Operators Use the Six Factors

During normal power operation, operators most directly manipulate f (by adjusting boron concentration or control rod position). They also monitor p through moderator temperature indicators and P_TNL / P_FNL through core power distribution. η and ε are set by the fuel and change only over the fuel cycle as fissile material is consumed.

During a xenon transient (xenon-135 building up after a power reduction), parasitic absorption rises sharply, driving f downward and making the reactor subcritical unless compensated by withdrawing control rods or reducing boron concentration.

Safety Perspective

Criticality control is a life-safety matter. Uncontrolled supercriticality — a prompt-critical excursion — releases energy so rapidly that no mechanical system can respond in time. Plant procedures, fuel-loading controls, and administrative limits on control rod withdrawal all exist to keep k-eff within safe bounds. When performing any work that could affect neutron balance (fuel handling, boron dilution, reflector changes), always verify procedure authority, confirm plant mode, and follow all administrative hold-points. Lockout/tagout (LOTO) of reactivity control systems must be verified before maintenance on control rod drives or chemical-volume control systems. Radiation work permits and appropriate dosimetry are required any time you work near an operating or recently shut-down core.

Key terms9

Effective Multiplication Factor (k-eff)The ratio of neutrons in one generation to neutrons in the preceding generation in a finite reactor; k-eff = 1 is critical, > 1 is supercritical, < 1 is subcritical.
Reproduction Factor (η, eta)The average number of fast neutrons produced per thermal neutron absorbed in fuel; determined by fuel enrichment and isotopic composition.
Fast Fission Factor (ε, epsilon)The factor accounting for additional neutrons produced by fast-neutron fissions in U-238 before neutrons slow down; slightly greater than 1.0.
Resonance Escape Probability (p)The probability that a neutron slows from fast to thermal energies without being captured in the U-238 resonance absorption region.
Thermal Utilization Factor (f)The fraction of thermal neutrons absorbed specifically in fuel rather than in moderator, structure, or poisons; the factor most directly manipulated by operators through boron and control rods.
Thermal Non-Leakage Probability (P_TNL)The probability that a thermal neutron is absorbed within the core rather than leaking out through the core boundary.
Fast Non-Leakage Probability (P_FNL)The probability that a fast neutron remains within the core while slowing down to thermal energies rather than escaping through the boundary.
Prompt CriticalityA dangerous condition in which the chain reaction is sustained by prompt neutrons alone, without the delay provided by delayed neutrons, causing an extremely rapid power excursion.
Xenon TransientA reactivity disturbance caused by the buildup of xenon-135, a strong neutron absorber produced after a power reduction, which lowers the thermal utilization factor f and tends to drive the reactor subcritical.

Worked examples4

1. A simplified reactor model gives the following factor values: η = 2.02, ε = 1.03, p = 0.82, f = 0.88, P_TNL = 0.97, P_FNL = 0.96. Calculate k-eff and state the reactor condition.
  1. Multiply the first two factors: η × ε = 2.02 × 1.03 = 2.0806
  2. Multiply by p: 2.0806 × 0.82 = 1.7061
  3. Multiply by f: 1.7061 × 0.88 = 1.5014
  4. Multiply by P_TNL: 1.5014 × 0.97 = 1.4564
  5. Multiply by P_FNL: 1.4564 × 0.96 = 1.3981 ≈ 1.398
Answer: k-eff ≈ 1.40 — the reactor is supercritical; the neutron population is growing each generation. In practice, control rods would be inserted or boron concentration increased to bring k-eff back to 1.0.
2. An operator adds boric acid to the coolant, increasing parasitic absorption. The thermal utilization factor f drops from 0.88 to 0.76 while all other factors remain unchanged (η = 2.02, ε = 1.03, p = 0.82, P_TNL = 0.97, P_FNL = 0.96). Calculate the new k-eff.
  1. Calculate the product of all factors except f: 2.02 × 1.03 × 0.82 × 0.97 × 0.96 = ?
  2. Step a — η × ε: 2.02 × 1.03 = 2.0806
  3. Step b — × p: 2.0806 × 0.82 = 1.7061
  4. Step c — × P_TNL: 1.7061 × 0.97 = 1.6549
  5. Step d — × P_FNL: 1.6549 × 0.96 = 1.5887
  6. Step e — × new f: 1.5887 × 0.76 = 1.2074 ≈ 1.207
Answer: k-eff ≈ 1.21. The reactor is still supercritical but the boron addition moved it significantly closer to critical. Additional boron would be needed to reach k-eff = 1.0 for steady power operation.
3. During a xenon transient, xenon-135 buildup increases neutron absorption such that f falls from 0.88 to 0.62. All other factors are unchanged from the baseline in Example 1 (η = 2.02, ε = 1.03, p = 0.82, P_TNL = 0.97, P_FNL = 0.96). Find k-eff and determine the reactor condition.
  1. Reuse the sub-product from Example 2 before applying f: product without f = 1.5887
  2. Multiply by the new f = 0.62: 1.5887 × 0.62 = 0.9850 ≈ 0.985
Answer: k-eff ≈ 0.985 — the reactor is subcritical. The xenon transient has suppressed f enough to drive the chain reaction below self-sustaining. The operator would need to withdraw control rods or reduce boron concentration to restore criticality.
4. Two small research reactors differ only in core size. Reactor A has P_TNL = 0.94 and P_FNL = 0.93; Reactor B (larger core) has P_TNL = 0.98 and P_FNL = 0.97. All other factors are: η = 2.05, ε = 1.03, p = 0.80, f = 0.87. Calculate k-eff for each and explain the physical difference.
  1. Calculate the common sub-product (η × ε × p × f): 2.05 × 1.03 × 0.80 × 0.87
  2. 2.05 × 1.03 = 2.1115
  3. 2.1115 × 0.80 = 1.6892
  4. 1.6892 × 0.87 = 1.4696
  5. Reactor A k-eff: 1.4696 × 0.94 × 0.93 = 1.4696 × 0.8742 = 1.2849 ≈ 1.285
  6. Reactor B k-eff: 1.4696 × 0.98 × 0.97 = 1.4696 × 0.9506 = 1.3970 ≈ 1.397
Answer: Reactor A k-eff ≈ 1.285; Reactor B k-eff ≈ 1.397. The larger core loses fewer neutrons through leakage, so both non-leakage probabilities are higher, producing a significantly higher k-eff. This illustrates why minimum critical mass concepts are essential to fuel-handling safety.

The math in this lesson1

Learners multiply the six factors to compute k-effective and judge criticality.
A-SSE.1
Brush up in the math halls at newSchoolWorks.com:
In class: Structured note-taking lecture: instructor derives the six-factor formula step by step; students maintain a running definition table and record which plant system or mechanism controls each factor. · k-eff sensitivity exercise: using a simplified spreadsheet model (instructor-provided), students vary one factor at a time (e.g., increase absorption fraction f by adding boron) and record the effect on k-eff, then explain in one sentence the physical meaning of each change. · Criticality scenario discussion: instructor presents three written reactor scenarios (fuel loading, normal operation, xenon transient) and student teams must determine whether the reactor is subcritical, critical, or supercritical, citing the controlling factor and its physical basis; teams present reasoning to class.
Materials: Instructor-provided spreadsheet (Excel or Google Sheets), scientific calculators, printed six-factor formula reference sheet, whiteboard, Lamarsh & Baratta textbook
Check: Written scenario analysis: given two reactor conditions, student must correctly classify k-eff state and identify the dominant contributing factor. Pass mark 80% (at least 4 of 5 questions correct).

Practice check8

Answer each question, then check it. Nothing is recorded; this is your own practice.

Reactor Theory / NRC Non-Licensed Operator Prep
1. Which factor in the six-factor formula represents the fraction of thermal neutrons absorbed in fuel rather than in the moderator or structural materials?
Reactor Control / NRC Non-Licensed Operator Prep
2. An operator dissolves additional boric acid in the reactor coolant. What is the most direct effect on k-eff and why?
Reactor Theory / NUCP Uniform Curriculum
3. A reactor is operating at steady power. Which statement correctly describes its criticality state?
Reactor Physics Calculations / NUCP Uniform Curriculum
4. Using the six-factor formula with η = 2.00, ε = 1.00, p = 0.80, f = 0.90, P_TNL = 1.00, P_FNL = 1.00, what is k-eff?
Reactor Transient Behavior / NRC Non-Licensed Operator Prep
5. Xenon-135 builds up in the core after a power reduction. Which six-factor parameter is most directly and immediately reduced by this buildup, and in which direction does k-eff move?
Reactor Design / NUCP Uniform Curriculum
6. Which of the following physical changes would most likely increase the fast non-leakage probability P_FNL?
Criticality Assessment / NRC Non-Licensed Operator Prep
7. A reactor scenario shows k-eff = 0.94. A student team states the reactor is 'nearly critical and safe to operate for power production.' Which response best corrects this assessment?
Industrial Safety / OSHA 10 & Radiation Protection
8. A maintenance team is preparing to work on the chemical-volume control system, which manages reactor coolant boron concentration. From a reactivity-control safety standpoint, what is the most critical administrative requirement before work begins?
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