🚧 Under construction — VoTechWorks is being built. A free tech program — complimentary, as our commitment to get America working.
voTechWorksGrade 13 · a vocational technology learning center, by urbanicity
newSchoolWorks.com › VoTechWorks › Building & Construction › Elevator Mechanic (pre-apprentice) › Certification Exam Preparation: NEIEP/IUEC Entry & NAEC CET › Lesson 2
BLD-ELEV10-09 · Lesson 2 · 12 clock hours · practice

Targeted Domain Review: Safety, Electrical, and Trade Math

Objective. Students will answer practice items in the safety/OSHA, electrical theory/electronics, and trade math domains at 75 % or higher by working through mapped drills, worked examples, and timed mini-quizzes.

⚠ Pending professional review

This lesson, its worked examples and its practice questions has not yet been verified by a licensed professional engineer or master tradesperson or by a certification or approval body. It is a study draft and may contain errors. Do not use it as instructions for work on a job site or on live equipment. Always follow your instructor, your supervising professional, and current official references and regulations.

VoTechWorks program approval and accreditation are still in progress. Credentials are issued only by the certifying bodies named in each program, after their own exams.

Why Targeted Domain Review Matters

The NEIEP/IUEC Apprenticeship Entry assessment and the NAEC Certified Elevator Technician (CET) exam both draw heavily from three domains: safety and OSHA regulations, electrical theory and electronics, and trade math. Scoring 75 % or higher on each domain is the benchmark you must meet—both in this course and on the actual credentials. This lesson walks you through the key content in each domain, shows you how to attack exam-style questions, and gives you a repeatable study method.

Domain 1: Safety and OSHA

Lockout/Tagout (LOTO) is governed by OSHA 29 CFR 1910.147 for general industry and is referenced extensively in elevator work. The six steps of LOTO are: (1) notify affected employees, (2) identify all energy sources, (3) shut down the equipment, (4) isolate energy sources, (5) apply lockout or tagout devices, and (6) verify zero energy state before beginning work. Every technician applies their own lock—never rely on someone else's lock to protect you.

Electrical hazard categories are defined by NFPA 70E. Personal protective equipment (PPE) selection depends on the incident energy level at the work location. At minimum, voltage-rated gloves and safety glasses are required when working on or near exposed energized parts. Arc-flash boundaries determine how close you may approach without additional PPE.

Fall protection under OSHA 29 CFR 1926.502 (construction) requires protection at elevations of six feet or more. In elevator hoistways—classified as a leading edge and a hole hazard—guardrails, personal fall arrest systems, or covers must be in place. Pit work often requires a ladder rated for the load and a fixed means of egress.

Confined space awareness: An elevator pit or machine room can qualify as a permit-required confined space when it contains or has the potential to contain a serious hazard (engulfment, atmospheric, or mechanical). Always test the atmosphere with a calibrated gas monitor before entry, and follow your employer's written permit program.

First aid and CPR: OSHA requires that a person trained in first aid be available when a medical facility is not within a reasonable response time. On a jobsite, know the location of the first-aid kit and the AED, and maintain current CPR/AED certification.

Study tip: When reviewing a missed safety question, locate the exact CFR section on your reference card, read the regulatory language, and write one sentence explaining what the rule requires and why. That act of writing cements the concept.

Domain 2: Electrical Theory and Electronics

Electrical questions on both exams test your ability to apply formulas, read circuits, and interpret NEC tables—not just memorize definitions.

Ohm's Law: V = I × R (Voltage = Current × Resistance). Rearrange as needed: I = V ÷ R or R = V ÷ I.

Power: P = V × I. For purely resistive AC circuits, P (watts) = V × I × power factor. On DC circuits, power factor = 1, so P = V × I.

Series circuits: Total resistance R_T = R₁ + R₂ + … Current is the same through every component; voltage divides.

Parallel circuits: 1/R_T = 1/R₁ + 1/R₂ + … Voltage is the same across every branch; current divides.

Transformer ratios: V_primary / V_secondary = N_primary / N_secondary. If you increase turns, you increase voltage (step-up); decrease turns, decrease voltage (step-down).

Motor starting current: Induction motors draw significantly higher current at startup (often five to seven times the full-load amperage). Controllers use reduced-voltage starters or variable-frequency drives (VFDs) to limit this inrush.

Conductor ampacity: Always check NEC ampacity tables for the conductor size, insulation type, and ambient temperature correction. Bundling conductors requires an additional derating factor.

Study tip: Work every electrical problem in writing, showing each formula and substitution. Verify your answer against NEC tables before the mini-quiz.

Domain 3: Trade Math

Elevator work requires quick, accurate math. Practice until these feel automatic.

Unit conversions: Know that 1 foot = 12 inches, 1 psi = 1 pound per square inch, 1 gallon ≈ 231 cubic inches, 1 meter ≈ 3.281 feet. Metric prefixes (kilo-, milli-, centi-) appear in hydraulic and electrical problems.

Hydraulic pressure-force-area: Pressure (psi) = Force (lb) ÷ Area (in²). Rearrange to find force or area. This formula governs hydraulic elevator ram sizing.

Mechanical advantage (MA): MA = Load ÷ Effort, or for a rope system, MA = number of rope segments supporting the load. Higher MA means less effort but more rope travel.

Rope-to-sheave ratios: The fleet angle and the D/d ratio (sheave diameter to rope diameter) affect rope life. A larger D/d ratio means less bending stress and longer rope life.

Counterweight loading: Counterweight = Car weight + (Capacity × 40–50 %). If capacity is 2,000 lb and the balance factor is 40 %, the counterweight balances the car plus 800 lb of live load. Adjust the percentage as given in the problem.

Study tip: During the 45-second-per-item timed drill, write the formula first, substitute numbers, then calculate. If you are stuck after 30 seconds, mark the item and move on—return if time permits.

Before the Mini-Quizzes

Organize your reference materials: OSHA summary cards, NEC ampacity tables, electrical formulas sheet, and hydraulic formula card. You may use these during practice but not during the graded mini-quizzes. The goal is to internalize the content so the reference cards become a check, not a crutch. Any domain below 75 % triggers a 15-item remediation set assigned by your instructor, followed by a re-quiz. Use that remediation as an opportunity—not a penalty.

Key terms9

Lockout/Tagout (LOTO)An OSHA-required safety procedure (29 CFR 1910.147) in which energy sources are isolated and physically locked before servicing equipment, ensuring the machine cannot be energized while workers are exposed.
Ohm's LawThe fundamental electrical relationship V = I × R, stating that voltage equals current multiplied by resistance; used to calculate any one of the three values when the other two are known.
AmpacityThe maximum current in amperes a conductor can carry continuously under specified conditions without exceeding its insulation temperature rating, as listed in NEC tables.
Transformer RatioThe relationship between primary and secondary voltages (and turns) in a transformer: V_primary / V_secondary = N_primary / N_secondary; used to step voltage up or down.
Mechanical Advantage (MA)The ratio of load to applied effort in a mechanical system; in a rope-and-sheave system it equals the number of rope segments supporting the load, reducing the force needed to lift the car.
Permit-Required Confined SpaceA space large enough to enter and perform work, with limited means of entry or exit, that contains or has the potential to contain a serious safety or health hazard, requiring a written entry permit and atmospheric testing before entry.
Incident EnergyThe amount of thermal energy impressed on a surface at a given distance during an electrical arc-flash event, measured in calories per square centimeter (cal/cm²); used to select appropriate arc-rated PPE under NFPA 70E.
Counterweight Balance FactorThe percentage of rated car capacity added to the car weight to determine counterweight mass; typically 40–50 %, it minimizes the motor torque needed to move the car in both directions.
Hydraulic Pressure FormulaPressure (psi) = Force (lb) ÷ Area (in²); the foundational formula for sizing hydraulic elevator rams, selecting pumps, and calculating relief-valve settings.

Worked examples4

1. A hoistway lighting circuit runs at 120 V. The total resistance of the circuit is 24 Ω. What current flows through the circuit, and what is the power consumed?
  1. Step 1 – Identify the formula for current: I = V ÷ R.
  2. Step 2 – Substitute values: I = 120 V ÷ 24 Ω = 5 A.
  3. Step 3 – Identify the power formula: P = V × I.
  4. Step 4 – Substitute values: P = 120 V × 5 A = 600 W.
Answer: Current = 5 A; Power = 600 W.
2. A control transformer has 480 V on the primary winding with 960 turns. The secondary must supply 120 V. How many turns are required on the secondary winding?
  1. Step 1 – Write the transformer ratio formula: V_primary / V_secondary = N_primary / N_secondary.
  2. Step 2 – Substitute known values: 480 / 120 = 960 / N_secondary.
  3. Step 3 – Solve for N_secondary: N_secondary = 960 × (120 ÷ 480).
  4. Step 4 – Calculate: N_secondary = 960 × 0.25 = 240 turns.
Answer: The secondary winding requires 240 turns.
3. A hydraulic elevator car weighs 3,600 lb. The jack plunger has a diameter of 6 inches. What pressure (psi) must the hydraulic system produce to lift the car? (Use Area = π × r²; use π ≈ 3.1416.)
  1. Step 1 – Find the radius of the plunger: r = 6 ÷ 2 = 3 inches.
  2. Step 2 – Calculate the plunger area: A = 3.1416 × (3)² = 3.1416 × 9 = 28.27 in².
  3. Step 3 – Apply the hydraulic pressure formula: Pressure = Force ÷ Area.
  4. Step 4 – Substitute values: Pressure = 3,600 lb ÷ 28.27 in² ≈ 127.3 psi.
Answer: The system must produce approximately 127 psi to lift the car.
4. A roping system uses 4 rope segments supporting the elevator car. The car and its rated load together weigh 6,000 lb. What tension (force) does each rope segment carry, and what is the mechanical advantage of this system?
  1. Step 1 – Identify the mechanical advantage: MA = number of rope segments supporting the load = 4.
  2. Step 2 – Calculate tension per rope segment: Tension = Total Load ÷ MA = 6,000 lb ÷ 4 = 1,500 lb.
  3. Step 3 – Confirm mechanical advantage interpretation: the machine only needs to exert 1,500 lb of pull to support a 6,000 lb load, giving MA = 4.
  4. Step 4 – State the result clearly.
Answer: Each rope segment carries 1,500 lb of tension; the mechanical advantage is 4.

The math in this lesson2

Learners use the transformer turns ratio to find secondary turns for 480 V to 120 V.
6.RP.3A-CED.4
Brush up in the math halls at newSchoolWorks.com:
In class: Work through a 30-item safety drill covering OSHA lockout/tagout procedures, electrical hazard categories, fall protection requirements, confined-space awareness, PPE selection, and first-aid/CPR responsibilities; after self-scoring, consult OSHA 29 CFR 1910 and 1926 reference summaries to correct each missed item and write a one-sentence rationale for the correct answer. · Complete six electrical theory worked-example sets—Ohm's Law, series and parallel circuits, power calculations, transformer ratios, motor starting current, and conductor ampacity—solving each problem step by step, then verify answers using the NEC reference tables and electrical formulas sheet before attempting a 20-item timed electrical mini-quiz. · Practice 25 trade math problems under timed conditions (45 seconds per item): unit conversions (imperial and metric), hydraulic pressure-force-area problems, mechanical advantage calculations, rope-to-sheave ratios, and percentage calculations for counterweight loading; review every incorrect answer with a peer using worked-solution cards.
Materials: Domain-specific question banks (safety, electrical, math), OSHA 29 CFR 1910 and 1926 summary reference cards, NEC ampacity and formula reference tables, electrical formulas sheet, hydraulic formula cards, scientific calculators, worked-solution card sets, whiteboard for group problem-solving
Check: Three graded mini-quizzes (safety 30 items, electrical 20 items, math 25 items); students must score 75 % or higher on each; any student below 75 % on a domain completes an instructor-assigned remediation set of 15 additional items in that domain and re-quizzes before Lesson 3.

Practice check8

Answer each question, then check it. Nothing is recorded; this is your own practice.

Safety / OSHA
1. During a LOTO procedure on an elevator controller, a technician applies a lockout device and then checks the start button to confirm the equipment will not energize. This final verification step is best described as:
Safety / OSHA
2. An elevator pit has limited means of entry, is large enough to enter, and the oxygen level measured by the gas monitor reads 19.0 %. Under OSHA confined-space rules, the immediate action is to:
Safety / OSHA
3. A worker is performing tasks in an elevator hoistway during new construction. At what height above a lower level does OSHA 29 CFR 1926.502 require fall protection for construction activities?
Electrical Theory
4. Two resistors are connected in parallel: R₁ = 12 Ω and R₂ = 6 Ω. The supply voltage is 24 V. What is the total current drawn from the supply?
Electrical Theory
5. A step-down transformer has a primary voltage of 240 V and a secondary voltage of 24 V. If the primary winding has 500 turns, how many turns does the secondary winding have?
Electrical Theory
6. According to NEC requirements, when conductors are bundled together in a raceway beyond the allowed number, the technician must apply a correction factor that does which of the following?
Trade Math
7. An elevator car weighs 2,500 lb. The counterweight balance factor is 45 %. The rated capacity of the car is 2,000 lb. What is the counterweight mass?
Trade Math
8. A hydraulic jack plunger has a cross-sectional area of 20 in². The system pressure is 250 psi. What upward force does the jack exert on the elevator car?
Record this lesson on my transcript. Sign in with your key and enrollment email to record lessons (enroll free if you have no key). This page stays open to read and practise.
← Previous lessonProgram planNext lesson →