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BLD-ELEC05-06 · Lesson 3 · 20.5 clock hours · theory

NEC Article 430 — Sizing and Code Compliance

Objective. Students apply NEC Article 430 to calculate branch-circuit conductor ampacity, select overcurrent protection devices, and size disconnecting means for a given motor load.

Why Article 430 Matters

Electric motors are the single largest category of electrical load in commercial and industrial buildings. NEC Article 430 is the dedicated section of the National Electrical Code that governs how conductors, overcurrent protection, controllers, and disconnects must be sized and installed for motor circuits. Because motor starting currents can be six to ten times the full-load running current, the rules here differ from ordinary branch-circuit rules in Article 210. Understanding Article 430 is essential for passing your NCCER assessments and for working legally and safely on motor installations.

Structure of Article 430

Article 430 is divided into parts. The three parts you will use most often are:

Keep your codebook tabbed and annotated by part. During work on a real job or on an exam problem, you must be able to move quickly between these sections and the associated tables.

Part II — Sizing Branch-Circuit Conductors

Section 430.22 states that a conductor supplying a single motor must have an ampacity of not less than 125% of the motor's full-load current (FLC). The FLC is not read from the motor nameplate; it is taken from the NEC tables:

Using the table value rather than the nameplate protects the circuit from motors that may be rewound or replaced with a slightly different unit in the future.

Formula: Minimum conductor ampacity = FLC (from table) × 1.25

Once you have the minimum ampacity, select the smallest standard wire gauge from NEC Table 310.12 (or 310.16 for 60/75/90 °C conductors) whose ampacity equals or exceeds that value.

Part II — Overcurrent Protection (Branch-Circuit Short-Circuit and Ground-Fault Protection)

Section 430.52 governs the breaker or fuse that protects the branch-circuit conductors against short circuits and ground faults. This device is not sized at 125% of FLC like the conductors. Because of high inrush current during starting, it is sized using Table 430.52, which gives maximum percentages of FLC by motor type and protective device type. Common values include:

If the calculated value does not match a standard device rating, Section 430.52(C)(1) permits rounding up to the next standard size, provided the result does not exceed the maximums in Table 430.52. Standard sizes are listed in Section 240.6(A).

Part VII — Motor Controllers

A controller is any device used to start and stop the motor. It must have an ampere or horsepower rating sufficient for the motor. Magnetic contactors with overload relays — called motor starters — are the most common type. The overload relay provides overload protection (distinct from the branch-circuit overcurrent protection), tripping on sustained overcurrent caused by mechanical overload or a locked rotor. Overloads are sized according to Section 430.32, typically at 115–125% of motor nameplate FLA depending on the service factor.

Part IX — Disconnecting Means

Every motor and its controller must have an accessible disconnecting means (Section 430.102). The disconnect must:

1. Be in sight of the motor and the driven machinery (within 50 feet and visible) — or be lockable in the open position when in sight is not practical.

2. Have an ampere rating of at least 115% of the motor's FLC from the applicable table (Section 430.110).

3. Be capable of being locked open so workers can perform lockout/tagout (LOTO) before servicing equipment.

Safety: Lockout/Tagout and PPE

Motors store energy — electrical, mechanical (rotating parts), and sometimes thermal. Before any work on a motor or its control circuit:

Never assume a motor is off because it is not turning — a motor stopped by a tripped overload can restart automatically when it cools.

Putting It Together

For any motor problem, follow this sequence:

1. Identify voltage and phase; find FLC in Table 430.248 or 430.250.

2. Multiply FLC × 1.25 → minimum conductor ampacity → select wire gauge.

3. Multiply FLC by the Table 430.52 percentage for your device type → select standard overcurrent device size.

4. Multiply FLC × 1.15 → minimum disconnect ampere rating.

5. Check that all selections comply with any additional conditions noted in Article 430.

Practice this sequence on every problem until it is automatic.

Key terms9

Full-Load Current (FLC)The current a motor draws at its rated horsepower and voltage, taken from NEC Tables 430.248 (single-phase) or 430.250 (three-phase) for circuit design — not from the motor nameplate.
Branch-circuit conductor ampacityThe current-carrying capacity of the wire supplying the motor; NEC Section 430.22 requires it to be at least 125% of the motor's table FLC.
Branch-circuit short-circuit and ground-fault protectionThe fuse or circuit breaker that protects motor branch-circuit conductors from short circuits and ground faults; sized per NEC Section 430.52 and Table 430.52, not at 125% of FLC.
Overload protectionA device (usually the overload relay in a motor starter) that interrupts the motor circuit when sustained overcurrent from mechanical overload threatens to damage the motor windings; governed by NEC Section 430.32.
Motor controllerAny switch or device used to start and stop a motor; must have a rating adequate for the motor's horsepower and voltage as required by NEC Part VII of Article 430.
Disconnecting meansA switch or circuit breaker required by NEC Section 430.102 to isolate the motor and controller from the supply; must be in sight of the motor, rated at least 115% of table FLC, and capable of being locked open for lockout/tagout.
Inverse-time circuit breakerA standard thermal-magnetic breaker whose trip time decreases as overcurrent increases; Article 430 allows it to be sized up to 250% of motor FLC for branch-circuit protection.
Dual-element (time-delay) fuseA fuse with separate elements for overload and short-circuit protection; allows motor starting inrush without nuisance opening and may be sized up to 175% of motor FLC under Article 430.
Lockout/Tagout (LOTO)An energy-control procedure (OSHA 29 CFR 1910.147 / 1926.417) requiring workers to de-energize equipment, apply a personal lock and warning tag, and verify zero energy before servicing motors or controls.

Worked examples4

1. A single-phase, 240 V, 5 hp motor will be protected by a dual-element time-delay fuse. Find: (a) the minimum conductor ampacity, (b) the maximum fuse size, and (c) the minimum disconnect rating.
  1. Step 1 — Find FLC from Table 430.248: For a single-phase 240 V, 5 hp motor, Table 430.248 gives FLC = 28 A.
  2. Step 2 — Minimum conductor ampacity (Section 430.22): 28 A × 1.25 = 35 A. Select the smallest conductor from Table 310.12 with ampacity ≥ 35 A. At 75 °C, 10 AWG copper = 35 A. Use 10 AWG copper minimum.
  3. Step 3 — Maximum fuse size (Section 430.52 and Table 430.52): Dual-element fuse maximum = 175% of FLC. 28 A × 1.75 = 49 A. The next standard fuse size at or below 49 A is 45 A (standard sizes per Section 240.6(A): 40, 45, 50 …). Because 49 A is not a standard size and rounding up to 50 A does not exceed the 175% maximum of the table, Section 430.52(C)(1) permits using 50 A. Use 50 A dual-element fuse.
  4. Step 4 — Minimum disconnect rating (Section 430.110): 28 A × 1.15 = 32.2 A. Select a disconnect rated at least 32.2 A; a standard 60 A fusible disconnect is the typical next available size.
Answer: (a) 10 AWG copper (35 A ampacity); (b) 50 A dual-element time-delay fuse; (c) disconnect rated at least 32.2 A (use 60 A standard size).
2. A three-phase, 480 V, 10 hp motor will be protected by an inverse-time (standard) circuit breaker. Find: (a) the minimum conductor ampacity, (b) the maximum breaker size, and (c) the minimum disconnect ampere rating.
  1. Step 1 — Find FLC from Table 430.250: For a three-phase 460 V, 10 hp motor (NEC tables use 460 V for 480 V systems), FLC = 14 A.
  2. Step 2 — Minimum conductor ampacity (Section 430.22): 14 A × 1.25 = 17.5 A. From Table 310.12 at 75 °C, 12 AWG copper = 20 A. Use 12 AWG copper minimum.
  3. Step 3 — Maximum breaker size (Section 430.52 and Table 430.52): Inverse-time breaker maximum = 250% of FLC. 14 A × 2.50 = 35 A. The next standard breaker size at or below 35 A is 35 A (standard sizes: 30, 35, 40 …). 35 A is a standard size and does not exceed 250%, so use a 35 A inverse-time breaker.
  4. Step 4 — Minimum disconnect rating (Section 430.110): 14 A × 1.15 = 16.1 A. A standard 30 A disconnect exceeds this; use a 30 A disconnect minimum.
Answer: (a) 12 AWG copper (20 A ampacity); (b) 35 A inverse-time circuit breaker; (c) disconnect rated at least 16.1 A (use 30 A standard size).
3. A three-phase, 208 V, 3 hp motor will be protected by a dual-element time-delay fuse. Find: (a) the minimum conductor ampacity, (b) the maximum fuse size.
  1. Step 1 — Find FLC from Table 430.250: For a three-phase 200 V (NEC table value closest to 208 V), 3 hp motor, FLC = 10.6 A. (Note: Always use the table voltage column equal to or just below the actual system voltage when an exact match is unavailable; verify against your current codebook.)
  2. Step 2 — Minimum conductor ampacity (Section 430.22): 10.6 A × 1.25 = 13.25 A. From Table 310.12 at 75 °C, 14 AWG copper = 15 A ≥ 13.25 A. Use 14 AWG copper minimum (also verify that no other NEC section, such as a minimum 12 AWG requirement on the job spec, increases this).
  3. Step 3 — Maximum fuse size (Section 430.52 and Table 430.52): Dual-element fuse maximum = 175% of FLC. 10.6 A × 1.75 = 18.55 A. The next standard fuse size at or below 18.55 A is 15 A (standard sizes: 15, 20 …). Rounding up to 20 A would exceed the 175% ceiling, so check whether Section 430.52(C)(1) permits it — only if 15 A causes nuisance opening; otherwise use 15 A. For this problem, use 15 A dual-element fuse as the code-compliant maximum without exceeding 175%.
Answer: (a) 14 AWG copper (15 A ampacity); (b) 15 A dual-element time-delay fuse.
4. A single-phase, 120 V, 1 hp motor is to be installed. Determine (a) the FLC, (b) the minimum conductor ampacity, and (c) the minimum disconnect rating.
  1. Step 1 — Find FLC from Table 430.248: For a single-phase 115 V (NEC table column for 120 V systems), 1 hp motor, FLC = 16 A.
  2. Step 2 — Minimum conductor ampacity (Section 430.22): 16 A × 1.25 = 20 A. From Table 310.12 at 75 °C, 12 AWG copper = 20 A. Use 12 AWG copper minimum.
  3. Step 3 — Minimum disconnect rating (Section 430.110): 16 A × 1.15 = 18.4 A. A standard 30 A disconnect exceeds this requirement; use a 30 A disconnect minimum.
Answer: (a) FLC = 16 A; (b) 12 AWG copper (20 A ampacity); (c) disconnect rated at least 18.4 A (use 30 A standard size).
In class: Guided code-book navigation: instructor walks through Article 430 part by part; students tab and annotate their codebooks for branch circuits (Part II), motor controllers (Part VII), and disconnects (Part IX). · Sizing problems set: students work individually through eight written problems covering single-phase 120/240 V and three-phase 208/480 V motors, selecting wire gauge, breaker or fuse rating, and disconnect ampere rating. · Pair review: partners exchange completed problem sets and verify answers against NEC tables, then discuss discrepancies with the class.
Materials: Current NEC codebook; NCCER Electrical Level 2 Motors module; NEC Tables 430.52, 430.248, 430.250, 430.52 (condensed handout); scientific calculators
Check: Eight-problem quiz scored by instructor; minimum 80% (7 of 8 correct) required; students who score below 80% complete an alternate problem set with instructor coaching before the next lesson.

Practice check8

Answer each question, then check it. Nothing is recorded; this is your own practice.

NCCER Electrical Level 2 — Motors and Controls
1. According to NEC Section 430.22, the minimum ampacity of a conductor supplying a single continuous-duty motor must be at least what percentage of the motor's full-load current from the applicable NEC table?
NCCER Electrical Level 2 — Motors and Controls
2. When sizing conductors for a three-phase motor circuit under Article 430, the full-load current value used for calculations must be taken from:
NCCER Electrical Level 2 — Motors and Controls
3. Under NEC Table 430.52, the maximum rating of an inverse-time circuit breaker used for motor branch-circuit short-circuit and ground-fault protection is what percentage of the motor's full-load current?
NCCER Electrical Level 2 — Motors and Controls
4. A single-phase 240 V 5 hp motor has a table FLC of 28 A. Using a dual-element time-delay fuse (maximum 175%), what is the calculated maximum fuse size before selecting a standard rating?
NCCER Electrical Level 2 — Motors and Controls
5. NEC Section 430.110 requires the disconnecting means for a motor to have an ampere rating of at least what percentage of the motor's full-load current from the applicable table?
OSHA 10 — Electrical Safety
6. A technician needs to service a motor controller. Before removing the cover, which action must be performed first under OSHA lockout/tagout requirements?
NCCER Electrical Level 2 — Motors and Controls
7. A three-phase 460 V 10 hp motor has a table FLC of 14 A. What is the minimum ampacity required for the branch-circuit conductors?
NCCER Electrical Level 2 — Motors and Controls
8. According to NEC Section 430.102, the disconnecting means for a motor must be located:
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