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newSchoolWorks.com › VoTechWorks › Manufacturing & Marine › Industrial Maintenance › Mechanical Drives: Belts, Chains, Gears, and Couplings › Lesson 2
MFG-INDU16-02 · Lesson 2 · 13 clock hours · theory

Mechanical Drive Fundamentals: Power, Torque, and Speed Ratios

Objective. Students will calculate driven-shaft speed, torque, and horsepower for a two-stage drive system using speed-ratio and power formulas with no more than 5% error.

⚠ Pending professional review

This lesson, its worked examples and its practice questions has not yet been verified by a licensed engineer or certified journey-level tradesperson or by a certification or approval body. It is a study draft and may contain errors. Do not use it as instructions for work on a job site or on live equipment. Always follow your instructor, your supervising professional, and current official references and regulations.

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Why Mechanical Drives Matter

A motor rarely connects directly to the machine it powers. Almost always, a mechanical drive system — belts and sheaves, chains and sprockets, or gear sets — sits between the motor and the load. That drive system does two jobs: it transmits power from one shaft to another, and it changes speed and torque to match what the load actually needs. Understanding how speed, torque, and horsepower relate to each other is the foundation of every drive calculation you will make in this program and on the job.

The Three Quantities and How They Connect

Rotational speed (RPM) is the number of complete revolutions a shaft makes in one minute.

Torque is the twisting force on a shaft, measured in pound-feet (lb·ft) or pound-inches (lb·in). Think of it as how hard the shaft is being twisted, not how fast it is spinning.

Horsepower (HP) is the rate at which work is done. For rotating shafts, the relationship is:

```

HP = (Torque [lb·ft] × RPM) / 5,252

```

This constant (5,252) comes from the definition of horsepower and the conversion between linear and rotational units. It appears in every standard mechanical drives reference. Rearranged:

```

Torque (lb·ft) = (HP × 5,252) / RPM

```

These two formulas let you move between any two of the three quantities when the third is known. Power is conserved in an ideal drive (no friction losses). In real drives, a small percentage of power is lost to heat and friction, but for sizing calculations you start with the assumption of 100% efficiency unless an efficiency value is given.

Speed Ratios: The Core of Drive Design

Whenever two rotating components are connected by a belt, chain, or mesh, their speeds are linked by the ratio of their diameters (for sheaves/pulleys) or tooth counts (for sprockets and gears).

For belt drives (sheaves) and chain drives (sprockets):

```

Speed Ratio = Driver Diameter (or Teeth) / Driven Diameter (or Teeth)

Driven RPM = Driver RPM × (Driver Diameter / Driven Diameter)

```

A small driver turning a large driven sheave slows the shaft down and multiplies torque. A large driver turning a small driven sheave speeds the shaft up and reduces torque.

For gear drives:

```

Driven RPM = Driver RPM × (Driver Teeth / Driven Teeth)

```

The formula is identical in form; only the physical quantity used (tooth count instead of diameter) changes.

Two-Stage Drives

Many industrial systems use two stages in series — for example, a belt drive from the motor to an intermediate shaft, then a chain drive from that shaft to the final load. You apply the speed ratio formula twice:

1. Calculate the intermediate shaft speed using Stage 1 ratio.

2. Use that intermediate speed as the input for Stage 2 to find the final driven speed.

Overall ratio of a two-stage drive equals the product of the two individual ratios:

```

Overall Ratio = Ratio₁ × Ratio₂

Final Driven RPM = Motor RPM / Overall Ratio

```

Torque at the output shaft (assuming no losses):

```

Output Torque = Motor Torque × Overall Ratio

```

Always verify that the output HP calculated from the final speed and torque matches the motor nameplate HP. A mismatch larger than your allowed tolerance signals an arithmetic error.

Reading a Motor Nameplate

The motor nameplate is your starting point for any drive calculation. Key values to read:

Safety Points

Mechanical drives are designed and sized at a desk, but they are installed and maintained around rotating machinery. Follow these rules every time:

Sizing errors are also a safety issue. An undersized drive overheats and fails unexpectedly. An oversized drive can generate torque levels that damage connected equipment or injure workers when a jam occurs. Accurate calculation protects people and machines alike.

Key terms9

TorqueThe rotational or twisting force acting on a shaft, typically measured in pound-feet (lb·ft) or pound-inches (lb·in) in US practice.
Horsepower (HP)A unit of power equal to the rate of doing work; for rotating shafts it is calculated as (Torque in lb·ft × RPM) ÷ 5,252.
Speed RatioThe ratio of driver diameter (or tooth count) to driven diameter (or tooth count); it determines how much the drive multiplies or reduces shaft speed.
DriverThe component — sheave, sprocket, or gear — that receives power from the motor and transmits it to the drive system.
DrivenThe component — sheave, sprocket, or gear — that receives power from the driver and transfers it to the load shaft.
Two-Stage DriveA drive system in which two separate drive pairs (e.g., a belt drive followed by a chain drive) are connected in series through an intermediate shaft, multiplying the individual speed ratios.
Motor NameplateThe data plate affixed to a motor by the manufacturer, listing rated HP, full-load RPM, voltage, phase, frame size, and service factor, among other values.
Service Factor (SF)A nameplate multiplier indicating the degree of overload a motor can sustain for limited periods without damage; a value of 1.15 means up to 15% above rated load.
Lockout/Tagout (LOTO)An OSHA-required procedure for de-energizing and physically locking out equipment so it cannot be started while maintenance or inspection work is being performed.

Worked examples4

1. A motor runs at 1,750 RPM and drives a belt drive. The driver sheave diameter is 4 inches and the driven sheave diameter is 12 inches. What is the driven shaft speed?
  1. Write the speed ratio formula: Driven RPM = Driver RPM × (Driver Diameter ÷ Driven Diameter).
  2. Substitute values: Driven RPM = 1,750 × (4 ÷ 12).
  3. Calculate the ratio: 4 ÷ 12 = 0.3333.
  4. Multiply: 1,750 × 0.3333 = 583.3 RPM.
Answer: Driven shaft speed ≈ 583 RPM (rounded to the nearest whole RPM).
2. A motor nameplate shows 10 HP at 1,750 RPM. What is the full-load torque at the motor shaft?
  1. Write the torque formula: Torque (lb·ft) = (HP × 5,252) ÷ RPM.
  2. Substitute values: Torque = (10 × 5,252) ÷ 1,750.
  3. Calculate the numerator: 10 × 5,252 = 52,520.
  4. Divide: 52,520 ÷ 1,750 = 30.01 lb·ft.
Answer: Full-load motor torque ≈ 30 lb·ft.
3. A two-stage drive is connected as follows — Stage 1 (belt): driver sheave 6 in, driven sheave 18 in; Stage 2 (chain): driver sprocket 12 teeth, driven sprocket 36 teeth. Motor speed is 1,800 RPM. Find the final driven shaft speed.
  1. Calculate Stage 1 ratio: 6 ÷ 18 = 0.3333; Intermediate shaft RPM = 1,800 × 0.3333 = 600 RPM.
  2. Calculate Stage 2 ratio: 12 ÷ 36 = 0.3333; Final shaft RPM = 600 × 0.3333 = 200 RPM.
  3. Verify using overall ratio: Overall Ratio = (18 ÷ 6) × (36 ÷ 12) = 3 × 3 = 9; Final RPM = 1,800 ÷ 9 = 200 RPM. Results match.
Answer: Final driven shaft speed = 200 RPM.
4. Using the same two-stage drive from Example 3, the motor produces 5 HP at 1,800 RPM. Assuming no power losses, what is the torque at the final driven shaft (200 RPM)?
  1. Confirm that power is conserved: the driven shaft also transmits 5 HP (no losses assumed).
  2. Apply the torque formula at the driven shaft: Torque = (HP × 5,252) ÷ RPM.
  3. Substitute: Torque = (5 × 5,252) ÷ 200 = 26,260 ÷ 200 = 131.3 lb·ft.
  4. Cross-check using ratio: Motor torque = (5 × 5,252) ÷ 1,800 = 14.59 lb·ft; Output torque = 14.59 × 9 (overall ratio) = 131.3 lb·ft. Results match.
Answer: Output torque at final driven shaft ≈ 131 lb·ft.

The math in this lesson2

Learners compute driven shaft speed from sheave diameters and sprocket teeth in single and two-stage drives.
6.RP.3A-CED.4
Brush up in the math halls at newSchoolWorks.com:
In class: Instructor-led lesson on the relationships between rotational speed (RPM), torque, and horsepower; students use calculators to work through sample problems as the instructor solves them on the board. · Worksheet set: students solve 12 problems covering single-stage and two-stage drives, computing output speed from sheave/sprocket diameters and gear tooth counts, then output torque and HP. · Pair activity: students are given a motor nameplate and a load requirement, then must determine whether the drive is appropriately sized, justify their answer in writing, and present to the class.
Materials: NCCER Industrial Maintenance Trainee Guide (Mechanical Drives module), scientific calculators, motor nameplates (samples), drive ratio worksheet packet, whiteboard
Check: 12-problem worksheet graded by instructor; students must score 80% or higher; errors in unit conversion or formula selection are flagged for remediation before Lesson 3.

Practice check8

Answer each question, then check it. Nothing is recorded; this is your own practice.

NCCER Industrial Maintenance – Mechanical Drives
1. A driver sheave has a diameter of 5 inches and spins at 1,200 RPM. The driven sheave has a diameter of 15 inches. What is the driven shaft speed?
MSSC CPT – Manufacturing Processes and Production
2. Which formula correctly calculates horsepower from torque and rotational speed?
NCCER Industrial Maintenance – Mechanical Drives
3. A motor nameplate reads 15 HP at 1,750 RPM. What is the full-load torque at the motor shaft (to the nearest lb·ft)?
NCCER Industrial Maintenance – Mechanical Drives
4. In a two-stage drive, Stage 1 has a speed ratio of 3:1 and Stage 2 has a speed ratio of 4:1. A motor runs at 1,800 RPM. What is the final driven shaft speed?
MSSC CPT – Safety
5. Before adjusting or replacing a drive belt on a running conveyor, a technician must FIRST:
NCCER Industrial Maintenance – Mechanical Drives
6. A driven gear has 60 teeth and its driver gear has 20 teeth. If the driver spins at 900 RPM, what is the driven gear speed?
NCCER Industrial Maintenance – Mechanical Drives
7. A 10 HP motor running at 1,750 RPM drives a two-stage system with an overall speed ratio of 7:1. Assuming no power losses, what is the approximate torque at the output shaft?
MSSC CPT – Manufacturing Processes and Production
8. A motor nameplate shows a Service Factor of 1.15. What does this mean for normal continuous operation?
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