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TEC-ELEC48-02 · Lesson 4 · 12.5 clock hours · lab

Series DC Circuits and Kirchhoff's Voltage Law

Objective. Students will apply Kirchhoff's Voltage Law (KVL) to a multi-resistor series circuit, predicting each resistor's voltage drop, and confirm results with DMM measurements within ±5%.

⚠ Pending professional review

This lesson, its worked examples and its practice questions has not yet been verified by an industry-certified professional or by a certification or approval body. It is a study draft and may contain errors. Do not use it as instructions for work on a job site or on live equipment. Always follow your instructor, your supervising professional, and current official references and regulations.

VoTechWorks program approval and accreditation are still in progress. Credentials are issued only by the certifying bodies named in each program, after their own exams.

What Is a Series Circuit?

A series circuit has only one current path. Every component — resistors, lamps, or any other load — is connected end-to-end so the same current flows through each one. If you break the path anywhere, current stops everywhere. That single-path behavior is the key fact behind every calculation and every troubleshooting step in this lesson.

Kirchhoff's Voltage Law (KVL)

Gustav Kirchhoff stated the law in the mid-1800s, and it has been confirmed by countless measurements ever since: the algebraic sum of all voltages around any closed loop equals zero. In practical terms, this means the source voltage equals the sum of all the voltage drops across the resistors in the loop.

> KVL statement: V_source = V₁ + V₂ + V₃ + … + Vₙ

Each resistor in a series circuit drops a portion of the total supply voltage. A resistor with a larger resistance drops a larger share; a resistor with a smaller resistance drops a smaller share. The drops must add up exactly to the supply — no more, no less. This is not an approximation; it is a fundamental law of circuit behavior.

Calculating Voltage Drops in a Series Circuit

Follow these steps for any series circuit:

1. Find total resistance. Add all resistor values: R_total = R₁ + R₂ + R₃ + … + Rₙ

2. Find series current. Apply Ohm's Law: I = V_source ÷ R_total. This one current flows through every component.

3. Find each voltage drop. Apply Ohm's Law to each resistor: Vₙ = I × Rₙ

4. Verify with KVL. Sum all drops and confirm the total equals V_source.

Step 4 is your built-in check. If the sum does not equal the source voltage within rounding error, recheck your arithmetic before you touch the breadboard.

Using a DMM to Measure Voltage

A digital multimeter (DMM) measures voltage in parallel with the component — place the probes across the resistor, not in series with it. Set the DMM to DC Volts and select a range equal to or higher than the expected reading. Touch the red probe to the more-positive side and the black probe to the more-negative side for a positive reading.

For this lab, your measurements must fall within ±5% of the calculated value to confirm the prediction. Differences larger than that usually mean a wiring error, a wrong resistor, or a faulty connection.

KVL and Troubleshooting: The Open Circuit

KVL is your most powerful troubleshooting tool in a series circuit. When one element is open (broken wire, failed component, missing jumper), the full source voltage appears across the open, and zero volts appears across every good resistor. Here is why: with no current flowing, Ohm's Law says V = I × R = 0 × R = 0 V across each resistor. The source voltage is undiminished and must appear somewhere in the loop — it appears entirely across the open gap.

To locate an open in a series string:

This systematic voltage-measurement method is faster and safer than probing with a continuity tester on a live circuit.

Safety in This Lab

Electrical safety — The DC power supplies used in this lab operate at low voltages (typically 12 V or less) and are not a serious electrocution hazard at that level. However, safe work habits must be established now because they carry over to higher-voltage work later in the program.

There is no lockout/tagout requirement for bench-level DC supplies, but students must understand that the habit of de-energizing before rewiring protects both the worker and the equipment in every voltage class.

Connecting This Lesson to Your Credentials

KVL is tested directly on the ETA CET written examination. The BICSI Installer credential focuses on cabling systems, but an installer who understands how voltage distributes in a series DC path can diagnose powered cabling faults confidently. Mastering these fundamentals now builds the foundation for AC circuits, signal transmission, and the fiber-optic power-budget calculations you will encounter later in the program.

Key terms8

Series circuitA circuit with only one current path, so the same current flows through every component from source through each element and back to source.
Kirchhoff's Voltage Law (KVL)The principle that the algebraic sum of all voltages around any closed loop equals zero; equivalently, the source voltage equals the sum of all voltage drops in a series circuit.
Voltage dropThe reduction in electrical potential across a resistor (or other load) caused by current flowing through its resistance, calculated as V = I × R.
Total resistanceIn a series circuit, the sum of all individual resistor values: R_total = R₁ + R₂ + … + Rₙ.
Open circuitA break in the current path — such as a missing jumper, broken wire, or failed component — that stops current flow throughout the entire series loop.
DMM (Digital Multimeter)A test instrument that measures voltage, current, and resistance digitally; connected in parallel with a component to measure voltage across it.
Ohm's LawThe relationship V = I × R, where V is voltage in volts, I is current in amperes, and R is resistance in ohms.
Loop equationA KVL equation written for one closed loop in a circuit, listing the source voltage and all resistor voltage drops so their algebraic sum can be set to zero and solved.

Worked examples4

1. A series circuit has a 24 V supply and three resistors: R₁ = 100 Ω, R₂ = 150 Ω, R₃ = 50 Ω. Find the current and the voltage drop across each resistor. Verify with KVL.
  1. Find total resistance: R_total = 100 + 150 + 50 = 300 Ω
  2. Find series current using Ohm's Law: I = V_source ÷ R_total = 24 V ÷ 300 Ω = 0.08 A (80 mA)
  3. Find V₁: V₁ = I × R₁ = 0.08 A × 100 Ω = 8 V
  4. Find V₂: V₂ = I × R₂ = 0.08 A × 150 Ω = 12 V
  5. Find V₃: V₃ = I × R₃ = 0.08 A × 50 Ω = 4 V
  6. KVL check: V₁ + V₂ + V₃ = 8 + 12 + 4 = 24 V = V_source ✓
Answer: I = 80 mA; V₁ = 8 V, V₂ = 12 V, V₃ = 4 V. Sum equals 24 V — KVL confirmed.
2. A four-resistor series circuit has a 12 V supply. R₁ = 120 Ω, R₂ = 180 Ω, R₃ is unknown, R₄ = 60 Ω. The voltage drop across R₃ is measured as 2 V. Find R₃ and verify KVL.
  1. Find R_total using Ohm's Law once current is known. First find current from total voltage and total resistance — but R₃ is unknown, so use the measured V₃ to find I first.
  2. Find current from any known resistor pair or directly from V₃ and the loop. Use KVL to find the sum of remaining drops: V₁ + V₂ + V₄ = I×120 + I×180 + I×60 = I×360. Total drops must equal 12 V, so I×360 + 2 = 12, giving I×360 = 10 V, so I = 10 ÷ 360 = 0.02778 A ≈ 27.8 mA.
  3. Find R₃: R₃ = V₃ ÷ I = 2 V ÷ 0.02778 A ≈ 72 Ω
  4. Verify individual drops: V₁ = 0.02778×120 = 3.33 V; V₂ = 0.02778×180 = 5.00 V; V₄ = 0.02778×60 = 1.67 V
  5. KVL check: 3.33 + 5.00 + 2.00 + 1.67 = 12.00 V ✓
Answer: R₃ ≈ 72 Ω; I ≈ 27.8 mA. KVL confirmed: all drops sum to 12 V.
3. During the 'missing resistor' troubleshooting exercise, a five-resistor series circuit is powered by 15 V. A student measures 0 V across R₁, R₂, R₄, and R₅, but 15 V across R₃. What does this indicate, and why?
  1. Recall the open-circuit rule: when there is no current, V = I × R = 0 × R = 0 V across every resistor with current path.
  2. 0 V across R₁, R₂, R₄, and R₅ means no current is flowing — the series path is broken somewhere.
  3. 15 V across R₃ means the full source voltage appears across R₃. This is the signature of an open: the undiminished source voltage drops entirely across the break.
  4. Conclusion: R₃ is open (the jumper or component at that position is missing or broken). Replacing R₃ will restore circuit operation.
Answer: R₃ is the open fault. Full source voltage (15 V) across one element while all others read 0 V is the definitive KVL indicator of an open at that element.
4. A student builds a series circuit with a 9 V supply and four resistors: R₁ = 47 Ω, R₂ = 68 Ω, R₃ = 33 Ω, R₄ = 82 Ω. The DMM reads 1.97 V across R₃. Is this within the ±5% tolerance of the calculated value?
  1. Find R_total: 47 + 68 + 33 + 82 = 230 Ω
  2. Find I: I = 9 V ÷ 230 Ω = 0.03913 A ≈ 39.13 mA
  3. Calculate expected V₃: V₃ = 0.03913 A × 33 Ω = 1.291 V. Round to 1.29 V.
  4. Find ±5% window: 1.29 V × 0.95 = 1.226 V (lower); 1.29 V × 1.05 = 1.355 V (upper).
  5. Compare: measured 1.97 V is well outside 1.226–1.355 V range. This fails the ±5% check.
  6. Likely cause: wiring error (a resistor is possibly shorted or mis-valued), or the wrong resistor was installed for R₃.
Answer: Calculated V₃ ≈ 1.29 V. The measured 1.97 V is approximately 53% higher than calculated — far outside ±5%. A wiring or component error must be investigated before accepting the result.

The math in this lesson2

Learners total series resistance (300 ohms), find 80 mA, and verify voltage drops sum to 24 V by KVL.
A-SSE.1A-CED.4
Brush up in the math halls at newSchoolWorks.com:
In class: Guided problem set (8 problems) on KVL in series circuits: students solve for unknown voltages and verify the sum of drops equals the source voltage; instructor reviews common errors at the board. · Breadboard build: construct a four-resistor series circuit with a measured supply voltage; use DMM to measure voltage across each resistor and record in a KVL loop equation worksheet. · 'Missing resistor' troubleshooting exercise: instructor pre-wires a five-resistor series circuit with one resistor replaced by an open (missing jumper); student must locate the open using only voltage measurements and document the fault-finding steps.
Materials: Breadboards, resistors, DC power supply, DMM, KVL worksheet, lab report template, ETA CET Study Guide
Check: KVL worksheet scored; 6 of 8 problems correct = pass. Lab measurements within ±5%; troubleshooting fault found and documented with correct logic.

Practice check8

Answer each question, then check it. Nothing is recorded; this is your own practice.

ETA CET — DC Circuit Theory
1. In a series circuit, Kirchhoff's Voltage Law states that the source voltage equals:
ETA CET — DC Circuit Theory
2. Three resistors — 100 Ω, 200 Ω, and 300 Ω — are connected in series with an 18 V supply. What is the series current?
ETA CET — DC Circuit Theory
3. Using the same circuit as the previous question (18 V supply, 100 Ω, 200 Ω, 300 Ω in series, I = 30 mA), what is the voltage drop across the 200 Ω resistor?
ETA CET — Troubleshooting / DC Circuits
4. During troubleshooting of a five-resistor series circuit energized at 12 V, a technician measures 12 V across R₄ and 0 V across every other resistor. The most likely cause is:
ETA CET — Test Equipment and Measurement
5. When using a DMM to measure voltage across a resistor in a series circuit, the meter leads should be connected:
ETA CET — DC Circuit Theory
6. A series circuit has a 20 V source and four resistors. Measured drops are: V₁ = 4 V, V₂ = 7 V, V₃ = 5 V. If KVL holds, what is V₄?
ETA CET — Test Equipment and Measurement
7. A student's DMM measurement of a voltage drop is 5.60 V. The calculated expected value is 5.50 V. Which statement correctly evaluates this result?
ETA CET — Safety and Professional Practices
8. Which safety practice is most important when rewiring a breadboard series circuit during a lab exercise?
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