BLD-MASO04-08 · Lesson 2 · 12 clock hours · theory
Arch Math: Layout Geometry and Joint Calculations
Objective. Students will calculate rise, span, radius, skewback angle, number of voussoirs, and minimum-to-maximum joint width for a given semicircular or segmental arch, with all computed values within accepted rounding tolerance
⚠ Pending professional review
This lesson, its worked examples and its practice questions has not yet been verified by a licensed professional engineer or master tradesperson or by a certification or approval body. It is a study draft and may contain errors. Do not use it as instructions for work on a job site or on live equipment. Always follow your instructor, your supervising professional, and current official references and regulations.
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Why Arch Math Matters
An arch transfers load outward and downward to its supports through compression. Every brick (called a voussoir) must be cut or laid so that its bed joints, when extended, all converge at the same center point. If your geometry is off, joints open unevenly, the arch rocks, or mortar is stressed in tension — something masonry cannot tolerate. Getting the numbers right on paper before touching a brick saves material, time, and prevents structural failure.
Key Arch Geometry Terms
Span is the clear horizontal distance between supports (the opening width). Rise is the vertical distance from the spring line to the soffit at the crown. The spring line is the horizontal line where the arch begins to curve upward from its supports. The intrados is the inner curved surface (the underside you see when you look up). The extrados is the outer curved surface. The skewback is the angled cut or course at the base of the arch where voussoirs begin.
Semicircular Arch Layout
For a semicircular arch, the rise equals exactly half the span, so the radius equals half the span as well. The center point sits on the spring line at the midpoint of the opening.
To locate the center on graph paper, mark the two support points. Measure the span, find the midpoint, and mark it. That midpoint on the spring line is your center. Swing the radius from that center to define the intrados curve.
Divide the semicircle into an odd number of equal angular divisions so that one voussoir falls exactly at the crown (the top). An odd count — typically 7, 9, 11, or more depending on span — ensures symmetry and a single keystone.
The skewback angle for a semicircular arch at the spring line is always 90° measured from vertical, because the first bed joint must point directly at the center. For segmental arches, this angle varies and must be calculated.
Segmental Arch Layout
A segmental arch is a segment of a circle whose rise is less than half the span. You must calculate the radius from span and rise using the following formula derived from the geometry of a chord and its perpendicular bisector:
R = (4 × Rise² + Span²) ÷ (8 × Rise)
The center point lies below the spring line for a segmental arch. To find it, measure down from the midpoint of the spring line by a distance equal to (R − Rise).
The skewback angle (measured from horizontal at the spring line) equals the angle whose sine is (Half-Span ÷ R), computed as:
Skewback Angle = arcsin(Half-Span ÷ R)
Use your calculator's inverse-sine function (sin⁻¹). Round to the nearest whole degree for layout purposes unless the specification requires more precision.
Voussoir Count and Joint Calculations
Once you know the arc length, you can calculate the number of voussoirs. The arc length of a semicircular arch is:
Arc Length = π × R (half the circumference of a full circle)
For a segmental arch, arc length equals R × central angle in radians, where the central angle in radians = 2 × arcsin(Half-Span ÷ R) converted to radians (multiply degrees by π/180).
Each voussoir occupies the brick unit length plus one mortar joint on the intrados. Because joints taper, the intrados joint is narrower than the extrados joint. Standard practice limits the minimum joint width at the intrados to ¼ inch and the maximum joint width at the extrados to ¾ inch for most brick arches (verify with your project specification or the Brick Industry Association technical notes).
Joint taper per voussoir depends on the radial depth of the arch ring (extrados radius minus intrados radius). The formula is:
Taper = (Extrados Circumference − Intrados Circumference) ÷ Number of Joints
Or equivalently: Taper = (Depth of Arch Ring × 2π × Central Angle in degrees) ÷ (360 × Number of Joints)
If your taper calculation produces an intrados joint below ¼ inch, you must either add more voussoirs, increase the arch ring depth, or specify a purpose-made tapered brick unit (a rubbed or gauged arch unit).
Reading Dimensions Accurately
All layout measurements should be made to the nearest 1/16 inch. When using an architect's scale or framing square, read from the zero mark, hold the tool flat, and read at eye level to avoid parallax error. When using a construction calculator, confirm your unit settings (feet-inch-fractions vs. decimal inches) before entering values.
Safety Notes
Layout work is low-hazard, but the following apply:
- Graph paper and pencil work at a desk: keep the work area clear; a framing square has sharp corners — handle it with care and store it flat so it does not bend or fall.
- Construction calculator: electronic devices near dusty or wet masonry conditions can be damaged; keep it in a protective case when not in use.
- When you move from paper calculations to the job site to transfer layout marks, wear required PPE (hard hat, safety glasses, work boots with slip-resistant soles) because you will be working around masonry operations above.
- Never scale measurements from a printed drawing unless the drawing states it is "drawn to scale" and you have confirmed the print has not been reduced — always use the dimensioned numbers.
Key terms10
VoussoirA wedge-shaped masonry unit (brick or stone) that forms part of an arch; its tapered bed joints converge toward the arch's center point.
SpanThe clear horizontal distance between the two supports of an arch, measured at the spring line.
RiseThe vertical distance from the spring line to the highest point of the intrados (the crown) of the arch.
IntradosThe inner curved surface of an arch — the underside visible from below; the shorter arc of the arch ring.
ExtradosThe outer curved surface of an arch; because it is farther from the center point, its arc is longer than the intrados.
SkewbackThe angled bearing surface at the base of each side of an arch where the first voussoir rests; its angle is calculated so that the bed joint points toward the arch center.
Spring LineThe horizontal line at the level where an arch begins to curve upward from its supports; the reference datum for rise measurements.
Segmental ArchAn arch whose curve is a segment of a circle with a rise less than half the span, requiring a calculated radius and a skewback angle less than 90°.
Joint TaperThe difference in mortar joint width between the intrados (narrow side) and extrados (wide side) of a voussoir, necessary to achieve the radial alignment of bed joints.
KeystoneThe single voussoir at the crown of an arch, positioned at the top center; placing one keystone requires an odd number of voussoirs.
Worked examples4
1. A semicircular arch has a clear span of 48 inches. Find the rise, the radius, and the arc length of the intrados.
- Step 1 — Rise: For a semicircular arch, Rise = Span ÷ 2 = 48 ÷ 2 = 24 inches.
- Step 2 — Radius: R = Span ÷ 2 = 48 ÷ 2 = 24 inches. The center point is on the spring line at the midpoint of the opening.
- Step 3 — Arc length of intrados: Arc Length = π × R = 3.1416 × 24 = 75.40 inches. Round to 75 7/16 inches for layout.
Answer: Rise = 24 inches; Radius = 24 inches; Intrados arc length ≈ 75 7/16 inches.
2. A segmental arch has a clear span of 60 inches and a rise of 10 inches. Calculate the radius and the skewback angle.
- Step 1 — Apply the radius formula: R = (4 × Rise² + Span²) ÷ (8 × Rise).
- Step 2 — Compute numerator: 4 × 10² = 4 × 100 = 400; Span² = 60² = 3,600; 400 + 3,600 = 4,000.
- Step 3 — Compute denominator: 8 × Rise = 8 × 10 = 80.
- Step 4 — Radius: R = 4,000 ÷ 80 = 50 inches.
- Step 5 — Skewback angle: Half-Span = 60 ÷ 2 = 30 inches. sin(angle) = Half-Span ÷ R = 30 ÷ 50 = 0.600.
- Step 6 — Angle = arcsin(0.600) = 36.87°, rounded to 37° for layout.
Answer: Radius = 50 inches; Skewback angle ≈ 37°.
3. Using the segmental arch from the previous example (Span 60 in., Rise 10 in., R = 50 in.), the arch ring depth (intrados to extrados) is 3.75 inches. Standard modular brick is 3 5/8 inches long. Determine the number of voussoirs using 9 units, and check whether the joint taper is within the ¼-inch minimum to ¾-inch maximum range.
- Step 1 — Central angle: arcsin(30 ÷ 50) = 36.87°; total central angle = 2 × 36.87° = 73.74°.
- Step 2 — Convert to radians: 73.74 × (π ÷ 180) = 73.74 × 0.017453 = 1.2868 radians.
- Step 3 — Intrados arc length: Arc = R × central angle in radians = 50 × 1.2868 = 64.34 inches.
- Step 4 — Extrados radius: R_ext = R + arch ring depth = 50 + 3.75 = 53.75 inches.
- Step 5 — Extrados arc length: Arc_ext = 53.75 × 1.2868 = 69.17 inches.
- Step 6 — With 9 voussoirs there are 8 joints on the intrados and 8 joints on the extrados. Each voussoir occupies 3.625 inches at the intrados (no joint — we treat the brick length as the unit and the joints as the spacing between). Total intrados space for joints = 64.34 − (9 × 3.625) = 64.34 − 32.625 = 31.72 inches spread across 8 joints → intrados joint = 31.72 ÷ 8 = 3.965 inches. (This is too wide — reconsider: the brick unit here is placed radially so its 3 5/8-inch dimension is the radial depth, not the arc length. For the arc direction, use the nominal 2 3/4-inch (bed-face) dimension of a standard modular brick, which is approximately 2.75 inches.) Revised: total intrados arc space for 9 bricks = 9 × 2.75 = 24.75 inches; intrados joint space = 64.34 − 24.75 = 39.59 inches over 8 joints → average intrados joint = 39.59 ÷ 8 ≈ 4.95 inches. (Still too large — use 9 units as an illustration.) Intrados joint per unit ≈ 4.95 inches is unrealistic; in practice the designer would increase the voussoir count significantly. However, using the correct approach: taper per joint = (Arc_ext − Arc_int) ÷ Number of joints = (69.17 − 64.34) ÷ 8 = 4.83 ÷ 8 = 0.60 inches taper per joint.
- Step 7 — Interpret taper: If the intrados joint averages, say, 3/8 inch (0.375 in.), the extrados joint would be 0.375 + 0.60 = 0.975 inches — exceeding the ¾-inch maximum. The designer must increase voussoir count to reduce taper, or use purpose-made tapered units.
Answer: Joint taper = 0.60 in. per joint with 8 joints. At 9 voussoirs, extrados joints would exceed the ¾-inch maximum; more voussoirs or tapered brick units are required.
4. A semicircular arch has a span of 36 inches and an arch ring depth of 3.75 inches. The designer wants 7 voussoirs. Find the intrados and extrados joint widths, assuming each brick unit measures 2.75 inches along the arc face.
- Step 1 — Radius (intrados): R = 36 ÷ 2 = 18 inches.
- Step 2 — Intrados arc length: π × 18 = 56.55 inches.
- Step 3 — Extrados radius: 18 + 3.75 = 21.75 inches.
- Step 4 — Extrados arc length: π × 21.75 = 68.33 inches.
- Step 5 — Space occupied by brick faces at intrados: 7 × 2.75 = 19.25 inches.
- Step 6 — Total intrados joint space: 56.55 − 19.25 = 37.30 inches over 6 joints (there are n−1 = 6 joints between 7 units) → intrados joint = 37.30 ÷ 6 = 6.22 inches. This is far too wide, confirming that at the intrados the arc length per voussoir (brick face plus joint) must be calculated as arc ÷ n. Arc per voussoir at intrados = 56.55 ÷ 7 = 8.07 inches; intrados joint = 8.07 − 2.75 = 5.32 inches. This is impractical, so the correct interpretation: arc per voussoir includes the joint. For this arch, a designer would use the taper method. Taper per joint = (68.33 − 56.55) ÷ 6 = 11.78 ÷ 6 = 1.96 inches — far above limits. With 7 units, this span/ring-depth combination requires purpose-made tapered units. As a calculation demonstration: intrados joint target = ¼ inch; extrados joint = ¼ + 1.96 = 2.21 inches (exceeds maximum). Conclusion: increase voussoir count or change arch ring proportions.
- Step 7 — Summary: The math shows that with 7 voussoirs, intrados and extrados joints are outside accepted limits. The problem illustrates why designers must iterate voussoir count until joint widths fall between ¼ inch (min) and ¾ inch (max).
Answer: With 7 voussoirs, taper ≈ 1.96 in. per joint — out of range. Increase voussoir count or use tapered units. All dimensions must be recalculated until intrados joint ≥ ¼ in. and extrados joint ≤ ¾ in.
The math in this lesson3
Learners compute arch radius from span and rise, intrados arc length, skewback angle, and voussoir joint widths.
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In class: Instructor demonstrates the geometric relationships for a semicircular arch on graph paper: locating the center point, swinging the radius, dividing the arch into an odd number of equal divisions, and computing the skewback angle using basic trigonometry; students repeat the construction for a different span · Paired practice problems: each pair receives a design brief (brick unit size, nominal span, desired rise) and must calculate radius, number of brick units, joint taper at intrados and extrados, and total mortar joint count; pairs exchange papers and check each other's arithmetic · Construction calculator drill: students enter arch calculations using the Calculated Industries Construction Master or equivalent trade calculator, comparing results to hand calculations and reconciling any discrepancy greater than 1/16 inch
Materials: NCCER Masonry Level 2 textbook, graph paper, architect's scale, framing square, Calculated Industries Construction Master calculator (or equivalent), printed problem sets, pencils
Check: Graded problem set of six arch calculation scenarios; students must solve at least five of six correctly, with all critical dimensions within 1/16-inch rounding tolerance, to pass
Practice check8
Answer each question, then check it. Nothing is recorded; this is your own practice.
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