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newSchoolWorks.com › VoTechWorks › Building & Construction › Welding › Metallurgy for Structural and Pipe Welding › Lesson 2
BLD-WELD01-08 · Lesson 2 · 12 clock hours · theory

Atomic Structure, Crystal Lattices, and the Iron-Carbon System

Objective. Using a labeled iron-carbon phase diagram, the student correctly identifies phase regions, critical transformation temperatures, and the microstructures that form during slow cooling for steels ranging from 0.10% to 0.80% carbon.

Why Metallurgy Matters for Structural and Pipe Welding

Every time you strike an arc on structural steel or a pressure pipe, you are running a small heat-treatment experiment on the metal. Understanding what happens inside the steel—at the atomic level—lets you predict whether the finished weld will be tough and ductile or hard and crack-prone. That knowledge directly supports quality work under AWS D1.1, ASME Section IX, and NCCER performance standards.

Atomic Structure and Metallic Bonding

Steel is mostly iron atoms held together by metallic bonds—a "sea" of free electrons surrounds positively charged ion cores. This bonding gives steel its characteristic properties: electrical conductivity, ductility, and the ability to deform without fracturing under moderate stress. Carbon atoms, much smaller than iron atoms, fit into the spaces between iron atoms; this is called an interstitial solid solution.

Crystal Lattices in Iron

Solid iron does not have just one atomic arrangement. It shifts between two crystal structures depending on temperature:

The shift from BCC to FCC on heating—and back to BCC on cooling—is called an allotropic transformation. It is the foundation of all heat treatment and the reason welding affects the metal around the weld bead.

The Iron-Carbon Phase Diagram

The iron-carbon phase diagram is a map that shows which phase or mixture of phases is stable at any combination of temperature and carbon content. For structural and pipe welding, focus on the region from 0% to about 1.0% carbon and temperatures from room temperature up to roughly 2,800 °F (1,538 °C).

Key lines and points to know:

Phase regions relevant to welding:

| Region | Phases Present |

|---|---|

| Above A3 | Austenite only |

| Between A1 and A3 (hypoeutectoid) | Austenite + Ferrite |

| Below A1 (slow-cooled) | Ferrite + Pearlite |

| Above ~2.1% C (not structural) | Austenite + Cementite |

Cementite (iron carbide, Fe₃C) is a hard, brittle compound containing 6.67% carbon. It appears as layers in pearlite and as proeutectoid cementite in high-carbon steels.

Pearlite is a layered (lamellar) mixture of ferrite and cementite that forms when austenite of eutectoid composition cools slowly through the A1 line. It looks like fine stripes under a microscope—resembling mother-of-pearl, hence the name. Hypoeutectoid steels (less than 0.77% C) produce proeutectoid ferrite plus pearlite on slow cooling.

Microstructures Formed During Cooling

Cooling rate is the main variable a welder controls through preheat, interpass temperature, and heat input.

Hardness ranking (lowest to highest): Ferrite-Pearlite < Bainite < Martensite

Safety Note

Metallurgy lab activities involve projected high-intensity lamps and microscope work. Use eye protection rated for the light source in use. When handling printed chemical etchants used to prepare photomicrograph specimens, wear chemical-splash goggles and nitrile gloves; consult the SDS for the specific etchant. Never heat steel samples without proper PPE—leather gloves and face shield minimum. Apply lockout/tagout procedures on any furnace or polishing equipment before servicing.

Key terms10

FerriteThe body-centered cubic (BCC) form of iron; soft, ductile, magnetic, and able to dissolve only about 0.02% carbon at room temperature.
AusteniteThe face-centered cubic (FCC) form of iron, stable above the A1 line; non-magnetic and capable of dissolving up to about 2.1% carbon.
PearliteA lamellar mixture of ferrite and cementite that forms when austenite of eutectoid composition transforms slowly through the A1 temperature; moderate hardness and good toughness.
CementiteIron carbide (Fe₃C), containing 6.67% carbon; a hard, brittle compound that appears as layers in pearlite or as a proeutectoid phase in high-carbon steels.
MartensiteA very hard, brittle structure formed when austenite is quenched faster than the critical cooling rate, trapping carbon in a supersaturated body-centered tetragonal lattice.
Eutectoid PointThe specific composition (approximately 0.77% carbon) and temperature (approximately 1,333 °F / 723 °C) at which austenite transforms entirely to pearlite on slow cooling.
A1 Line (Lower Critical Temperature)The horizontal line on the iron-carbon diagram at approximately 1,333 °F (723 °C), below which austenite is unstable in plain-carbon steels.
A3 Line (Upper Critical Temperature)The boundary above which hypoeutectoid steel is fully austenitic; its temperature decreases as carbon content increases, meeting the A1 line at the eutectoid point.
BainiteA steel microstructure with a needle-like or feathery appearance formed at cooling rates between those producing pearlite and martensite; harder than ferrite-pearlite but tougher than martensite.
Heat-Affected Zone (HAZ)The region of base metal adjacent to the weld bead that has not melted but whose microstructure and properties have been altered by the heat of welding.

Worked examples4

1. A structural steel plate contains 0.20% carbon. It is heated above the A3 line and then allowed to cool slowly in still air (normalizing). Identify the expected microstructure at room temperature and estimate the approximate proportion of pearlite present.
  1. Step 1 – Classify the steel. 0.20% C is less than 0.77% C (eutectoid), so this is a hypoeutectoid steel.
  2. Step 2 – Trace the cooling path on the diagram. On slow cooling, the steel passes through the A3 line first, where proeutectoid ferrite begins to form. It continues cooling until the A1 line, where remaining austenite transforms to pearlite.
  3. Step 3 – Estimate phase proportions using the lever rule at a temperature just below A1. The eutectoid point is at 0.77% C; the ferrite boundary at A1 is approximately 0.02% C. Fraction pearlite = (0.20 − 0.02) / (0.77 − 0.02) = 0.18 / 0.75 ≈ 0.24.
  4. Step 4 – State the microstructure. Approximately 24% pearlite and 76% proeutectoid ferrite, giving a soft, ductile structure.
Answer: The room-temperature microstructure is approximately 24% pearlite and 76% proeutectoid ferrite. The steel is soft and ductile—typical of normalized mild structural steel.
2. A 0.40% carbon steel is welded without preheat in cold weather. The weld cools very rapidly. Predict the likely microstructure in the heat-affected zone and its consequence for weld quality.
  1. Step 1 – Identify the carbon level. 0.40% C is hypoeutectoid but high enough that rapid cooling can produce hard microstructures.
  2. Step 2 – Apply cooling rate logic. Very rapid cooling (faster than the critical cooling rate for this steel) suppresses both ferrite-pearlite and bainite formation. Carbon is trapped in the iron lattice.
  3. Step 3 – Identify the resulting microstructure. Rapid quench produces martensite in the HAZ.
  4. Step 4 – State the consequence. Martensite is hard and brittle. Combined with dissolved hydrogen from the welding atmosphere, this condition creates high risk of hydrogen-induced cold cracking (also called delayed cracking) in the HAZ. AWS D1.1 and ASME Section IX both address preheat requirements to slow cooling and prevent martensite formation.
Answer: The HAZ will likely contain martensite—a hard, brittle microstructure that significantly raises the risk of hydrogen-induced cold cracking. Proper preheat per the applicable code is required to slow the cooling rate and avoid this outcome.
3. Use the lever rule to find the weight fraction of cementite in a steel that contains 0.60% carbon, just below the A1 line (assume the phases present are ferrite at ~0.02% C and cementite at 6.67% C).
  1. Step 1 – Identify the tie-line endpoints. Ferrite composition = 0.02% C; Cementite composition = 6.67% C; alloy composition = 0.60% C.
  2. Step 2 – Apply the lever rule for cementite fraction. Fraction cementite = (0.60 − 0.02) / (6.67 − 0.02) = 0.58 / 6.65.
  3. Step 3 – Calculate. 0.58 ÷ 6.65 ≈ 0.0872.
  4. Step 4 – Interpret. About 8.7% of the microstructure by weight is cementite; the remainder (~91.3%) is ferrite. Because cementite is the hard component, even this modest fraction contributes to the overall strength and some reduction in ductility compared to a purer ferrite.
Answer: Approximately 8.7% cementite by weight, with the balance as ferrite. This small but significant cementite fraction (appearing within pearlite colonies) contributes to the steel's strength.
4. Rank the following three steel microstructures from softest to hardest, and briefly explain why the ranking is what it is: (a) ferrite-pearlite formed by slow cooling, (b) bainite formed by intermediate cooling, (c) martensite formed by rapid quenching.
  1. Step 1 – Consider ferrite-pearlite. Slow cooling allows full diffusion of carbon into equilibrium lamellae. The resulting structure has relatively wide ferrite regions (soft) and is the softest of the three.
  2. Step 2 – Consider bainite. Intermediate cooling partially suppresses diffusion, producing a finer needle-like structure. Carbon is less evenly distributed than in pearlite, increasing dislocation density and hardness above ferrite-pearlite.
  3. Step 3 – Consider martensite. Rapid quenching traps all carbon in a supersaturated, highly strained body-centered tetragonal lattice. The extreme lattice distortion resists dislocation movement, making martensite the hardest (and most brittle) of the three.
  4. Step 4 – State the ranking. Softest to hardest: ferrite-pearlite → bainite → martensite.
Answer: Softest to hardest: ferrite-pearlite < bainite < martensite. The increasing hardness reflects decreasing time for carbon diffusion during cooling, resulting in progressively more strained and distorted crystal structures.

The math in this lesson2

Learners apply the lever rule to find the cementite weight fraction in a 0.60% carbon steel.
6.RP.3A-SSE.1
Brush up in the math halls at newSchoolWorks.com:
In class: Label a blank iron-carbon phase diagram (ferrite, austenite, pearlite, cementite, eutectoid point, A1 and A3 lines) using a textbook reference and then reproduce it from memory on a second blank copy. · Work through a guided calculation worksheet: given carbon content and cooling rate, predict whether the resulting microstructure will be ferrite-pearlite, martensite, or bainite, and rank each for hardness. · Compare photomicrographs of ferrite-pearlite, martensite, and bainite microstructures under a demonstration microscope or projected digital images and record distinguishing features in a lab notebook entry.
Materials: Iron-carbon phase diagram poster and reproducible blank worksheet, Lincoln Electric Welding Metallurgy reference guide (or equivalent), digital photomicrographs of steel microstructures, scientific calculator
Check: Labeled diagram reproduced from memory with all required regions and temperatures correct; quiz on microstructure-property relationships; 80% minimum on combined 20-question assessment.

Practice check8

Answer each question, then check it. Nothing is recorded; this is your own practice.

Metallurgy and Materials — AWS SENSE / NCCER Welding
1. On the iron-carbon phase diagram, the A1 line represents which transformation temperature?
Metallurgy and Materials — AWS SENSE / NCCER Welding
2. What crystal structure does austenite have, and approximately how much carbon can it dissolve compared with ferrite?
Metallurgy and Materials — AWS D1.1 Structural Code / NCCER
3. A 0.77% carbon steel is cooled slowly from above the A3 line. Which single microstructure forms when it passes through the A1 temperature?
Weld Quality and Discontinuities — AWS D1.1 / ASME Sec. IX
4. Which microstructure formed in the heat-affected zone is most closely associated with hydrogen-induced cold cracking in structural welds?
Metallurgy and Materials — AWS SENSE / NCCER Welding
5. Using the lever rule, a 0.30% carbon steel just below the A1 line has ferrite at 0.02% C and cementite at 6.67% C. What is the approximate weight fraction of cementite?
Weld Quality and Process Variables — ASME Sec. IX / AWS D1.1
6. A welder is working on a high-carbon steel pipe in cold weather without preheat. The rapid cooling rate through the heat-affected zone is most likely to produce which microstructure?
Metallurgy and Materials — AWS SENSE / NCCER Welding
7. From softest to hardest, what is the correct order of the three steel microstructures: ferrite-pearlite, bainite, and martensite?
Safety and Health — General Industry / Trade Practice
8. When examining photomicrographs of steel microstructures in a lab activity, which personal protective equipment is the minimum requirement when handling chemically etched specimens?
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