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TEC-ELEC48-01 · Lesson 4 · 22 clock hours · theory

Ohm's Law, Decibels, and Signal Loss Math

Objective. Students will apply Ohm's Law, the power equation, and the decibel formula to calculate voltage, current, resistance, power, and signal gain or loss in circuits and cable systems, achieving 80 percent accuracy on graded problems.

⚠ Pending professional review

This lesson, its worked examples and its practice questions has not yet been verified by an industry-certified professional or by a certification or approval body. It is a study draft and may contain errors. Do not use it as instructions for work on a job site or on live equipment. Always follow your instructor, your supervising professional, and current official references and regulations.

VoTechWorks program approval and accreditation are still in progress. Credentials are issued only by the certifying bodies named in each program, after their own exams.

Why These Formulas Matter

Every circuit you wire, every cable run you test, and every signal path you trace depends on three foundational relationships: Ohm's Law, the power equations, and the decibel scale. Whether you are troubleshooting a faulty resistor on a circuit board or measuring signal loss in a fiber or coaxial cable run, these tools tell you exactly what the numbers should be — and whether something has gone wrong. Mastering them now prepares you for the ETA CET, ETA FOI/FOT, and BICSI Installer exams, and for daily work on the job.

Safety Before You Calculate

Before measuring any live circuit, observe these non-negotiable rules:

Calculation errors can also be a safety hazard — an undersized wire or resistor that you calculated incorrectly can overheat and start a fire. Always double-check your arithmetic before specifying components.

Ohm's Law: V = IR

Ohm's Law states that the voltage (V) across a resistor equals the current (I) through it multiplied by its resistance (R).

| Find | Formula |

|------|---------|

| Voltage | V = I × R |

| Current | I = V / R |

| Resistance | R = V / I |

Units: volts (V), amperes (A), ohms (Ω). Keep your units consistent — milliamps must be converted to amps before you plug into the formula.

Power Equations

Electrical power (P), measured in watts (W), describes how fast a circuit converts electrical energy. Three equivalent forms exist:

These are derived by substituting Ohm's Law into P = IV; all three are mathematically equivalent. Power calculations are critical for selecting fuses, wires, and power supplies that will not overheat.

The Decibel (dB) Scale

In telecom and electronics, signal levels often span many orders of magnitude. The decibel compresses that range into manageable numbers and allows you to add or subtract gains and losses instead of multiplying or dividing ratios.

For power ratios:

> dB = 10 × log₁₀(P₂ / P₁)

For voltage ratios (when comparing signals across equal impedances):

> dB = 20 × log₁₀(V₂ / V₁)

Key reference points to memorize:

| dB value | Power ratio | Meaning |

|----------|-------------|---------|

| 0 dB | 1:1 | No change |

| +3 dB | ≈ 2:1 | Power doubled |

| −3 dB | ≈ 1:2 | Power halved |

| +10 dB | 10:1 | Power ×10 |

| −10 dB | 1:10 | Power ÷10 |

A positive dB value means gain (amplifier); a negative dB value means loss (cable attenuation, splitter, connector). In a cable system, losses accumulate — you simply add the dB losses for each segment and connector in the path.

dBm: Absolute Power Reference

You will also see dBm, which expresses power relative to 1 milliwatt:

> dBm = 10 × log₁₀(P / 1 mW)

For example, 10 mW = +10 dBm; 0.1 mW = −10 dBm. Fiber optic link budgets and RF signal-level measurements are almost always expressed in dBm.

Applying dB to Cable Loss

Suppose a coaxial cable segment has a rated attenuation of 3 dB at a given frequency. If you input 20 mW, the output power is 10 mW. If you then pass through a connector rated at 0.5 dB loss, your total loss is 3.5 dB. You do not multiply; you add the losses. This additive property is the main reason the telecom industry uses decibels every day.

Using a Scientific Calculator

To evaluate log₁₀ on most scientific calculators:

1. Enter the argument (the number inside the log).

2. Press the log key (not ln, which is the natural log).

3. Multiply the result by 10 (for power) or 20 (for voltage).

Practice until this sequence is automatic — exam problems are timed.

Connecting to Your Credentials

Key terms8

Ohm's LawThe relationship V = IR, stating that voltage across a resistor equals the product of current through it and its resistance.
Resistance (R)The opposition to current flow in a conductor, measured in ohms (Ω).
Power (P)The rate at which electrical energy is converted, measured in watts (W); calculated as P = IV, P = V²/R, or P = I²R.
Decibel (dB)A logarithmic unit expressing the ratio of two power or voltage levels; positive values indicate gain, negative values indicate loss.
dBmA decibel value referenced to 1 milliwatt, used to express absolute signal power levels in telecom and fiber optic systems.
AttenuationThe reduction in signal power as it travels through a cable, connector, or other passive component, expressed in dB.
Link BudgetAn accounting of all gains and losses in a signal path from transmitter to receiver, used to verify that adequate signal level will be received.
Logarithm (log₁₀)The base-10 logarithm used in the decibel formula; the exponent to which 10 must be raised to equal a given number.

Worked examples4

1. A resistor is connected to a 12 V source and measures 4 A of current. Find (a) the resistance and (b) the power dissipated.
  1. Step 1 — Find resistance using Ohm's Law rearranged: R = V / I = 12 V / 4 A = 3 Ω
  2. Step 2 — Find power using P = I × V = 4 A × 12 V = 48 W
  3. Step 3 — Verify with alternate formula: P = I² × R = (4)² × 3 = 16 × 3 = 48 W ✓
Answer: R = 3 Ω; P = 48 W
2. A technician applies 9 V across a 270 Ω resistor. Calculate the current through the resistor and the power it dissipates.
  1. Step 1 — Find current: I = V / R = 9 V / 270 Ω = 0.0333 A (33.3 mA)
  2. Step 2 — Find power using P = V² / R = (9)² / 270 = 81 / 270 = 0.3 W
  3. Step 3 — Verify: P = I × V = 0.0333 A × 9 V ≈ 0.3 W ✓
Answer: I ≈ 33.3 mA; P ≈ 0.3 W
3. A fiber optic cable run delivers an output power of 0.5 mW when the transmitter launches 2 mW. How many dB of loss does the cable introduce?
  1. Step 1 — Identify the formula for power ratio in dB: dB = 10 × log₁₀(P₂ / P₁)
  2. Step 2 — Substitute values: P₂ = 0.5 mW (output), P₁ = 2 mW (input)
  3. Step 3 — Calculate the ratio: P₂ / P₁ = 0.5 / 2 = 0.25
  4. Step 4 — Take the log: log₁₀(0.25) = log₁₀(1/4) ≈ −0.602
  5. Step 5 — Multiply by 10: 10 × (−0.602) = −6.02 dB
  6. Step 6 — Interpret: the negative sign confirms this is a loss of approximately 6 dB.
Answer: The cable introduces approximately −6 dB of loss.
4. An amplifier increases a signal voltage from 0.1 V to 2 V across the same impedance. What is the gain in dB?
  1. Step 1 — Use the voltage ratio formula: dB = 20 × log₁₀(V₂ / V₁)
  2. Step 2 — Calculate the ratio: V₂ / V₁ = 2 / 0.1 = 20
  3. Step 3 — Take the log: log₁₀(20) ≈ 1.301
  4. Step 4 — Multiply by 20: 20 × 1.301 ≈ 26 dB
  5. Step 5 — Interpret: a positive value confirms this is a gain of approximately 26 dB.
Answer: Amplifier gain ≈ 26 dB

The math in this lesson2

Learners rearrange Ohm's law to find R = 12 V / 4 A = 3 ohms and P = 48 W, and compute decibel loss.
A-CED.4F-LE.4
Brush up in the math halls at newSchoolWorks.com:
In class: Work through a structured note-taking lecture on Ohm's Law (V = IR), the power equations (P = IV, P = V²/R, P = I²R), and the dB formula (dB = 10 log₁₀ P₂/P₁ for power, 20 log₁₀ V₂/V₁ for voltage) — students solve five demonstration problems alongside the instructor. · Complete a 30-problem worksheet in pairs, starting with single-variable Ohm's Law problems and progressing to multi-step problems that combine power and decibel calculations, such as determining how many dB of loss a cable introduces given input and output power in milliwatts. · Use a free online circuit simulator (such as Falstad's Circuit Simulator, which is publicly available) to build five simple resistive circuits, predict the voltage and current using hand calculation, then run the simulation and compare predicted to simulated values, documenting any discrepancy.
Materials: Scientific calculator, Ohm's Law reference card, decibel reference table, printed problem sets, computer with browser access for simulator, pencil and engineering paper
Check: 30-problem graded worksheet with 80 percent pass threshold (24 of 30); simulator comparison exercise graded on correct documentation — predicted versus actual values within 5 percent for full credit, with written explanation of any larger discrepancy.

Practice check8

Answer each question, then check it. Nothing is recorded; this is your own practice.

DC Circuits — ETA CET
1. A 24 V source is connected across a 6 Ω resistor. What is the current through the resistor?
DC Circuits — ETA CET
2. A technician needs to find the resistance of a component that drops 15 V with 50 mA flowing through it. What is the resistance?
DC Circuits — ETA CET
3. How much power is dissipated by a 100 Ω resistor carrying 200 mA?
Signal Level Math — ETA CET / ETA FOI/FOT
4. An amplifier receives a signal at 1 mW and outputs 10 mW. What is the gain expressed in dB?
Cabling Systems — BICSI Installer / ETA FOI/FOT
5. A coaxial cable segment has a loss of 3 dB and a connector at the far end has a loss of 0.5 dB. What is the total loss of the cable-plus-connector path?
Fiber Optics — ETA FOI/FOT
6. A fiber transmitter launches 1 mW into a cable. The receiver detects 0.1 mW. What is the path loss in dB?
DC Circuits — ETA CET
7. Which of the following is the correct formula to use when you know voltage and resistance but need to find power?
Signal Level Math — ETA CET / ETA FOI/FOT
8. A signal voltage drops from 4 V to 2 V across equal impedances as it passes through a passive filter. What is the insertion loss of the filter in dB?
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